C++ Program to Find the GCD and LCM of N Numbers

This is a C++ Program to find GCD and LCM of given two numbers.

Here is source code of the C++ Program to Find the GCD and LCM of n Numbers. The C++ program is successfully compiled and run on a Linux system. The program output is also shown below.

```
#include<iostream>
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#include<conio.h>
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#include<stdlib.h>
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using namespace std;
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```
 
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int gcd(int x, int y)
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{
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    int r = 0, a, b;
```

    a = (x > y) ? x : y; // a is greater number

    b = (x < y) ? x : y; // b is smaller number

```
 
```
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    r = b;
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    while (a % b != 0)
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    {
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        r = a % b;
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        a = b;
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        b = r;
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    }
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    return r;
```
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}
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```
 
```
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int lcm(int x, int y)
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```
{
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    int a;
```

    a = (x > y) ? x : y; // a is greater number

```
    while (true)
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    {
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        if (a % x == 0 && a % y == 0)
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            return a;
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        ++a;
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    }
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}
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```
 
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int main(int argc, char **argv)
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{
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    cout << "Enter the two numbers: ";
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    int x, y;
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    cin >> x >> y;
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    cout << "The GCD of two numbers is: " << gcd(x, y) << endl;

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    ;
```

    cout << "The LCM of two numbers is: " << lcm(x, y) << endl;

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    ;
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    return 0;
```
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}
```

Output:

$ g++ GCDLCM.cpp
$ a.out
 
Enter the two numbers: 
5
8
The GCD of two numbers is: 1
The LCM of two numbers is: 40
 
Enter the two numbers: 
100
50
The GCD of two numbers is: 50
The LCM of two numbers is: 100

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