This C Program calculates the Sum of Series 1 + 1/2 + 1/3 + 1/4 + … + 1/N. This program is used to find the sum of the given series.

Here is source code of the C Program to Find the Sum of Series 1 + 1/2 + 1/3 + 1/4 + … + 1/N. The C program is successfully compiled and run on a Linux system. The program output is also shown below.

`/*`

`* C Program to find the Sum of Series 1 + 1/2 + 1/3 + 1/4 + ... + 1/N`

`*/`

`#include <stdio.h>`

void main()

`{`

double number, sum = 0, i;

printf("\n enter the number ");

scanf("%lf", &number);

for (i = 1; i <= number; i++)

`{`

sum = sum + (1 / i);

if (i == 1)

printf("\n 1 +");

else if (i == number)

printf(" (1 / %lf)", i);

`else`

printf(" (1 / %lf) + ", i);

`}`

printf("\n The sum of the given series is %.2lf", sum);

`}`

Output: $ cc pgm.c $ a.out enter the number 4 1 + (1/2.000000) + (1/3.000000) + (1/4.000000) The sum of the given series is 2.08

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If you wish to look at other example programs on Mathematical Functions, go to C Programming Examples on Mathematical Functions. If you wish to look at programming examples on all topics, go to C Programming Examples.