This is a C program to find product of 2 numbers using recursion.

This C program finds the product of 2 numbers using recursion.

This C program using recursion, finds the product of 2 numbers without using the multiplication operator.

Here is the source code of the C program to display a linked list in reverse. The C program is successfully compiled and run on a Linux system. The program output is also shown below.

/* * C Program to find Product of 2 Numbers using Recursion */ #include <stdio.h> int product(int, int); int main() { int a, b, result; printf("Enter two numbers to find their product: "); scanf("%d%d", &a, &b); result = product(a, b); printf("Product of %d and %d is %d\n", a, b, result); return 0; } int product(int a, int b) { if (a < b) { return product(b, a); } else if (b != 0) { return (a + product(a, b - 1)); } else { return 0; } }

In this C program, reading two numbers using ‘a’ and ‘b’ variables respectively. The product() function is used to find the product of two numbers. Nested if else condition statement is used to check the value of ‘a’ variable is less than the value of ‘b’ variable.

If the condition is true then execute the statement. Compute the summation of the value of ‘a’ variable with the value. Otherwise, if the condition is false then execute else if condition statement. Check the condition that the value of ‘b’ variable is not equal to 0.

If the condition is true then execute the statement. Otherwise, if the condition is false then execute the else statement and return the null. Print the product of two numbers.

$ cc pgm20.c $ a.out Enter two numbers to find their product: 176 340 Product of 176 and 340 is 59840

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