C Program to find the sum of series 1^2 + 2^2 + …. + n^2.

This C Program calculates the Sum of Series 1^2 + 2^2 + …. + n^2. Then the Sum of the series 1^2 + 2^2 + …. + n^2 = n(n + 1)(2n + 1) / 6.

Here is source code of the C Program to Find the Sum of Series 1^2 + 2^2 + …. + n^2. The C program is successfully compiled and run on a Linux system. The program output is also shown below.

```
/*
```

 * C Program to find the sum of series 1^2 + 2^2 + …. + n^2.

```
 */
```
```
#include <stdio.h>
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```
 
```
```
int main()
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```
{
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```
    int number, i;
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    int sum = 0;
```
```
 
```

    printf("Enter maximum values of series number: ");

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    scanf("%d", &number);
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    sum = (number * (number + 1) * (2 * number + 1 )) / 6;

    printf("Sum of the above given series : ");

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    for (i = 1; i <= number; i++)
```
```
    {
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        if (i != number)
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```
            printf("%d^2 + ", i);
```
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        else
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            printf("%d^2 = %d ", i, sum);

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    }
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    return 0;
```
```
}
```

Output:
$ cc pgm18.c
$ a.out
Enter maximum values of series number: 4
Sum of the above given series : 1^2 + 2^2 + 3^2 + 4^2 = 30

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