C Program to Find Sum of Series 1^3 + 2^3 + 3^3 + … + n^3

This C Program calculates the Sum of Series 1^3 + 2^3 + 3^3 + … + n^3. Sum of the series 1^3 + 2^3 + 3^3 + … + n^3 = (n(n + 1) / 2)2

Here is source code of the C Program to Find the Sum of Series 1^3 + 2^3 + 3^3 + … + n^3. The C program is successfully compiled and run on a Linux system. The program output is also shown below.

```
/*
```

 * C Program to Find the Sum of Series 1^3 + 2^3 + 3^3 + … + n^3

```
 */
```
```
#include <stdio.h>
```
```
#include <math.h>
```
```
 
```
```
int main()
```
```
{
```
```
    int number, i;
```
```
    int sum = 0;
```
```
 
```

    printf("Enter the maximum values of series n: ");

```
    scanf("%d", &number);
```

    sum = pow(((number * (number + 1) ) / 2),2);

```
    printf("Sum of the series : ");
```
```
    for (i = 1; i <= number; i++)
```
```
    {
```
```
        if (i != number)
```
```
            printf("%d^3 + ", i);
```
```
        else
```

            printf("%d^3 = %d ", i, sum);

```
    }
```
```
    return 0;
```
```
}
```

Output:
$ cc pgm17.c
$ a.out
Enter the maximum values of series n: 5
Sum of the series : 1^3 + 2^3 + 3^3 + 4^3 + 5^3 = 225

If you find any mistake above, kindly email to [email protected]

« Prev - C Program to Find Two Odd Occurring Elements in an Array

» Next - C Program to Print Floyd’s Triangle

Related Posts:

Recommended Articles: