# C# Program to Print Number Triangle

This is a C# Program to display numbers in the form of triangle.

Problem Description

This C# Program Displays Numbers in the form of Triangle.

Problem Solution

Here the numbers are displayed in the form of a triangle.

Program/Source Code

Here is source code of the C# Program to Display Numbers in the form of Triangle. The C# program is successfully compiled and executed with Microsoft Visual Studio. The program output is also shown below.

```/*
*  C# Program to Display Numbers in the form of Triangle
*/
using System;
class Pascal
{
public static void Main()
{
int[,] arr = new int[8, 8];
for (int i = 0; i < 8; i++)
{
for (int k = 7; k > i; k--)
{   //For loop to print spaces
Console.Write(" ");
}

for (int j = 0; j < i; j++)
{
if (j == 0 || i == j)
{
arr[i, j] = 1;
}
else
{
arr[i, j] = arr[i - 1, j] + arr[i - 1, j - 1];
}
Console.Write(arr[i, j] + " ");
}
Console.WriteLine();

}
}
}```
Program Explanation

In this C# program, we are printing the numbers in the form of triangle. Pascal’s triangle is a triangular array of the binomial coefficients. The program consists of six integer type of variables named i, j, rows, array[][], k and num respectively. Out of this variable i, j and k have been defined to control the for loop, the integer ‘rows’ stores the limit of Pascal’s triangle entered by the user.

As the C program for Pascal’s triangle is executed, it first asks for the value of limit of the triangle. The program assigns ‘rows’ variable value with the value of ‘i’ variable; i.e., number of space with the limit of Pascal’s triangle, for loop in which ‘i’ is the loop control variable. Again, in order to control the space, a nested for loop with ‘k’ as a control variable is used.

Finally, for printing the elements in this program for Pascal’s triangle in C, another nested for loop of control variable ‘j’ has been used. The formula used to generate the numbers of Pascal’s triangle is:
Pascal triangle: array[i][j] = array[i – 1][j – 1] + array[i – 1][j].

Runtime Test Cases
```
1
1 1
1 2 1
1 3 3 1
1 4 6 4 1
1 5 10 10 5 1
1 6 15 20 15 6 1```

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