C# Program to Find Volume and Surface Area of Sphere

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This is a C# Program to find volume and surface area of a sphere.

Problem Description

This C# Program finds Volume and Surface Area of a Sphere.

Problem Solution

Here radius and height of the sphere are obtained from the user and the surface area and its volume its calculated.

Program/Source Code

Here is source code of the C# Program to find Volume and Surface Area of a Sphere. The C# program is successfully compiled and executed with Microsoft Visual Studio. The program output is also shown below.

/*
 * C# Program to find Volume and Surface Area of a Sphere
 */
using System;
using System.IO;
class program
{
    public static void Main()
    {
        double r, surface_area, volume;
        double PI = 3.14;
        Console.WriteLine("Enter the Radius of the Sphere: ");
        r = Convert.ToDouble(Console.ReadLine());
        surface_area =  4* PI * r * r;
        volume = (4.0 / 3) * PI * r * r * r;
        Console.WriteLine("Surface Area of Sphere is : {0} ", surface_area);
        Console.WriteLine("Volume of Sphere is : {0}", volume);
        Console.Read();
    }
}
Program Explanation

In this C# program, library function defined in <math.h> header file is used. We are reading the radius of the Sphere using ‘r’ variable. To compute the area and volume of the sphere the following formula is used

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Surface_area = 4 * Pi * r * r,

Volume = 4 / 3 * Pi * r * r * r

where Pi = 22/7.

Runtime Test Cases
 
Enter the Radius of Sphere : 5
Surface Area of Sphere is : 314
Volume of Sphere is : 523.333333333333333

Sanfoundry Global Education & Learning Series – 1000 C# Programs.

If you wish to look at all C# Programming examples, go to 1000 C# Programs.

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Manish Bhojasia - Founder & CTO at Sanfoundry
Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He lives in Bangalore, and focuses on development of Linux Kernel, SAN Technologies, Advanced C, Data Structures & Alogrithms. Stay connected with him at LinkedIn.

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