LISP Questions & Answers – Lexical Variables

This set of LISP Multiple Choice Questions & Answers (MCQs) focuses on “Lexical Variables”.

1. Which makes it possible to define sophisticated generator procedures that produce new values?
a) List
b) Variables
c) Encapsulation
d) None of the mentioned
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2. Which primitive enables you to define one procedure inside another?
a) Do
b) List
c) Primitive
d) Labels
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3. Which helps to produce nested fences?
a) Lets
b) List
c) Label
d) None of the mentioned
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4. Which do not produce nested fences?
a) Variables
b) Procedure calls
c) Fences
d) All of the mentioned
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5. Which makes nameless procedures into lexical closures?
a) $
b) #
c) #’
d) *
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6. What is the output of the given statement?

span class="sy0"> * (defun first-of-first-with-labels (l) (labels ((aux (m) (first m))) (first (aux 1))))
* (first-of-first-with-labels '((a b) (c d)))

a) A
b) B
c) C
d) D
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7. What is the output of the given statement?

span class="sy0"> * (defun power-of-two () (setf previous-power-of-two (* previous-power-of-two 2)))
* (power-of-two)
* (power-of-two)

a) 1
b) 2
c) 4
d) None of the mentioned
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8. What is the output of the given statement?

span class="sy0"> * (defun square (list-of-numbers) (mapcar #'(lambda (n) (*n n)) list-of-numbers))
* (square '(1 2 3))

a) 9
b) 1
c) 3
d) 1 4 9
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9. What is the output of the given statement?

span class="sy0"> * (setf square-procedures #'(lambda (n) (* n n)))
* (funcall square-procedure 2)

a) 1
b) 2
c) 3
d) 4
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10. What is the output of the given statement?

span class="sy0"> * (setf g1 (let ((previous-power-of-two 1)) #'(lambda () (setf previous-power-of-two (*previous-power-of-two 2)))))
* (g1)

a) G1
b) 0
c) Let
d) Error
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Sanfoundry Global Education & Learning Series – LISP Programming Language.

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