Continue & Goto Statements - C# Questions & Answers

This section of our 1000+ C# multiple choice questions focuses on Continue and Goto Statements in C# Programming Language.

1. What will be the output of the following C# code?

```
  static void Main(string[] args)
```
```
  {
```
```
      int i;
```

      Console.WriteLine("enter value of i:");

      i = Convert.ToInt32(Console.ReadLine());

```
      if (i < 7)
```
```
      {
```
```
          i++;
```
```
          continue;
```
```
      }
```

      Console.WriteLine("final value of i:" +i);

```
      Console.ReadLine();
```
```
  }
```

a) 12
b) 11
c) Compile time error
d) 13
View Answer

Answer: c
Explanation: ‘Continue’ loop cannot be used within ‘if’ loop. replace while with if(i <7).
Output: Compile time error.

2. What will be the output of the following C# code?

```
 static void Main(string[] args)
```
```
 {
```
```
     int i;
```

     Console.WriteLine("enter value of i:");

     i = Convert.ToInt32(Console.ReadLine());

```
     if ( i % 2 == 0)
```
```
         goto even:
```
```
     else
```
```
     {
```

         Console.WriteLine("number is odd:");

```
         Console.ReadLine();
```
```
     }
```
```
     even:
```

     Console.WriteLine("number is even:");

```
     Console.ReadLine();
```
```
 }
```
```
for i = 4.
```

a) number is odd
b) number is even
c) Compile time error
d) none of the mentioned
View Answer

Answer: c
Explanation: “Undefined label ‘even’ in main(). The syntax ‘goto even:’ is incorrect instead use ‘goto even;’.

Note: Join free Sanfoundry classes at Telegram or Youtube

3. What will be the output of the following C# code?

```
  static void Main(string[] args)
```
```
  {
```
```
      int i = 1, j;
```
```
      do
```
```
      {
```
```
          for (j = 1; ; j++)
```
```
          {
```
```
              if (j > 2)
```
```
                  break;
```
```
              if (i == j)
```
```
                  continue;
```

              Console.WriteLine(i + " " + j);

```
          }
```
```
          i++;
```
```
      } while (i < 3);
```
```
      Console.ReadLine();
```
```
  }
```

1 2 
2 1

2 1
1 2

1 3
2 1

1 1
2 1

View Answer

Answer: a
Explanation: for i = 1. When control enters in loop first if condition is checked for where j = 1 and as (j > 2) which is false. Control is now passed to console statement with i = 1 and j = 2. Now, in while condition value of ‘i’ reflected is 2 i.e i = 2 as i++. Since, (i < 3) control again enters in for loop with i = 2 but j = 1 not j = 2 for j++ and hence, again same condition executes for console statement.
Output : 1 2
2 1

4. What will be the output of the following C# code?

```
   static void Main(string[] args)
```
```
   {
```
```
       int i = 10 , j = 0;
```
```
       label:
```
```
       i--;
```
```
       if ( i > 0)
```
```
       {
```
```
           Console.WriteLine(i+ " ");
```
```
           goto label;
```
```
       }
```
```
       Console.ReadLine();
```
```
   }
```

a) 1 2 3 4 5 6 7 8 9 10
b) 10 9 8 7 6 5 4 3 2 1 0
c) 9 8 7 6 5 4 3 2 1
d) 10 9 8 7 6 5 4 3 2 1
View Answer

Answer: c
Explanation: for i = 10, loop executes for first time in ‘if’ loop as (i>0) i.e (9 > 0) and hence printing ‘9’. Similarly, label condition executes again go for (i–) i.e (9-1=8) and hence again prints i = 8. In this way looping condition executes as 9, 8 to 3, 2, 1.
OUTPUT :

9 8 7 6 5 4 3 2 1

5. What will be the output of the following C# code?

```
  static void Main(string[] args)
```
```
  {
```
```
      int i = 0, j = 0;
```
```
      while (i < 2)
```
```
      {
```
```
          l1: i--;
```
```
          while (j < 2)
```
```
          {
```

              Console.WriteLine("hi\n");

```
              goto l1;
```
```
          }
```
```
      }
```
```
      Console.ReadLine();
```
```
  }
```

a) hi hi hi
b) hi hi
c) hi
d) hi hi hi…..infinite times
View Answer

Answer: d
Explanation: Since, i– so, test condition for ‘i’ never satisfies it fails and hence infinite loop in occurs.
output:

hi hi hi.....

6. What will be the output of the following C# code?

```
  static void Main(string[] args)
```
```
  {
```
```
      int i = 0;
```
```
      if (i == 0)
```
```
      {
```
```
          goto label;
```
```
      }
```

      label: Console.WriteLine("HI...");

```
      Console.ReadLine();
```
```
  }
```

a) Hi…infinite times
b) Code runs prints nothing
c) Hi Hi
d) Hi…
View Answer

Answer: d
Explanation: for i = 0, if condition is satisfied as (i == 0). So, label statement is printed.
Output :

Hi

7. What will be the output of the following C# code?

```
  static void Main(string[] args)
```
```
  {
```
```
      int i = 0, j = 0;
```
```
      l1: while (i < 2)
```
```
      {  
```
```
          i++;
```
```
          while (j < 3)
```
```
          {
```

              Console.WriteLine("loop\n");

```
              goto l1;
```
```
          }
```
```
       }
```
```
      Console.ReadLine();
```
```
  }
```

a) loop is printed infinite times
b) loop
c) loop loop
d) Compile time error
View Answer

Answer: c
Explanation: Since outer while loop i.e while(i<2) executes only for two times. Hence, loop while executing third time for (j<3) could not be able to satisfy condition i<2 as i = 2. Hence, loop breaks and control goes out of loop.
Output :

loop loop.

8. What will be the output of the following C# code?

```
  static void Main(string[] args)
```
```
  {
```
```
      int i= 0,k;
```
```
      label: Console.WriteLine(i);
```
```
      if (i == 0)
```
```
          goto label;
```
```
      Console.ReadLine();
```
```
  }
```

a) 0 0 0 0
b) 0 0 0
c) 0 infinite times
d) 0
View Answer

Answer: c
Explanation: Since, if condition is always true. Loop will continue executing always without any end condition.
Output:

0 0 0....

9. What will be the output of the following C# code?

```
   static void Main(string[] args)
```
```
   {
```
```
       int i = 0;
```
```
       int j = 0;
```
```
       for (i = 0; i < 4; i++)
```
```
       {
```
```
           for (j = 0; j < 3; j++)
```
```
           {
```
```
               if (i > 1)
```
```
                   continue;
```

               Console.WriteLine("Hi \n");

```
           }
```
```
       }
```
```
       Console.ReadLine();
```
```
   }
```

a) Prints hi 4 times
b) Prints hi 3 times
c) Prints hi 6 times
d) Prints hi infinite times
View Answer

Answer: c
Explanation: None.
Output :

10. Select the output for the following set of code :

```
    static void Main(string[] args)
```
```
    {
```
```
        int a = 0;
```
```
        int i = 0;
```
```
        int b;
```
```
        for (i = 0; i < 5; i++)
```
```
        {
```
```
             a++;
```

             Console.WriteLine("Hello \n");

```
             continue;
```
```
        }
```
```
        Console.ReadLine();
```
```
    }
```

a) print hello 4 times
b) print hello 3 times
c) print hello 5 times
d) print hello infinite times
View Answer

Answer: c
Explanation: Condition executes until and unless i < 5. So, it prints “hello” until ‘i’ condition is satisfied.
Output :

             Hello
             Hello
             Hello
             Hello 
             Hello

11. What will be the output of the following C# code?

```
    static void Main(string[] args)
```
```
    {
```
```
        Console.WriteLine("HI");
```
```
        continue;
```
```
        Console.WriteLine("Hello");
```
```
        Console.ReadLine();
```
```
    }
```

a) Hi Hello
b) Hi
c) Hello
d) Compile time error
View Answer

Answer: d
Explanation: Absence of any loop condition in order to make decision of break or continue.

Sanfoundry Global Education & Learning Series – C# Programming Language.

To practice all areas of C# language, here is complete set of 1000+ Multiple Choice Questions and Answers.

« Prev - C# Questions & Answers – Do While Loop Statements

» Next - C# Questions & Answers – Fundamentals of Class

Related Posts:

Recommended Articles: