Chemical Engineering Questions and Answers – Heat of Solution, Dissolution and Mixing

This set of tricky Chemical Engineering questions and answers focuses on “Heat of Solution, Dissolution and Mixing”.

1. A mixture contains 20% of A with Heat Capacity 10 J/oC and 80% of B with Heat Capacity 5 J/oC, what is the Heat Capacity of mixture?
a) 6 J/oC
b) 7 J/oC
c) 8 J/oC
d) 9 J/oC
View answer

Answer: a
Explanation: Heat capacity of mixture = 0.2*10 + 0.8*5 = 2 + 4 = 6 J/oC.

2. A mixture contains 40% of A with Heat Capacity 15 J/oC and 60% of B with Heat Capacity 10 J/oC, what is the Heat Capacity of mixture?
a) 11 J/oC
b) 12 J/oC
c) 13 J/oC
d) 14 J/oC
View answer

Answer: b
Explanation: Heat capacity of mixture = 0.4*15 + 0.6*10 = 6 + 6 = 12 J/oC.

3. A mixture contains 50% of A with Heat Capacity 10 J/oC and 50% of B with Heat Capacity 20 J/oC, what is the Heat Capacity of mixture?
a) 12 J/oC
b) 15 J/oC
c) 17 J/oC
d) 18 J/oC
View answer

Answer: b
Explanation: Heat capacity of mixture = 0.5*10 + 0.5*20 = 15 J/oC.
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4. A mixture contains 20% of A with Heat Capacity 25 J/oC, 30% of B with Heat Capacity 20 J/oC, and 50% of C with Heat Capacity 10 J/oC, what is the Heat Capacity of mixture?
a) 10 J/oC
b) 14 J/oC
c) 16 J/oC
d) 20 J/oC
View answer

Answer: c
Explanation: Heat capacity of mixture = 0.2*25 + 0.3*20 + 0.5*10 = 16 J/oC.

5. A mixture contains 30% of A with Heat Capacity 10 J/oC, 30% of B with Heat Capacity 20 J/oC, and 40% of C with Heat Capacity 35 J/oC, what is the Heat Capacity of mixture?
a) 14 J/oC
b) 17 J/oC
c) 19 J/oC
d) 23 J/oC
View answer

Answer: d
Explanation: Heat capacity of mixture = 0.3*10 + 0.3*20 + 0.4*35 = 23 J/oC.
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6. What is the enthalpy of a mixture having 10% of A with enthalpy 10 J, and 90% of B with enthalpy 20 J?
a) 10 J
b) 15 J
c) 18 J
d) 19 J
View answer

Answer: d
Explanation: Heat capacity of mixture = 0.1*10 + 0.9*20 = 19 J.

7. What is the enthalpy of a mixture having 20% of A with enthalpy 15 J, and 80% of B with enthalpy 25 J?
a) 17 J
b) 19 J
c) 23 J
d) 28 J
View answer

Answer: c
Explanation: Heat capacity of mixture = 0.2*15 + 0.8*25 = 23 J.
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8. What is the enthalpy of a mixture having 40% of A with enthalpy 50 J, and 60% of B with enthalpy 25 J?
a) 30 J
b) 35 J
c) 40 J
d) 45 J
View answer

Answer: b
Explanation: Heat capacity of mixture = 0.4*50 + 0.6*25 = 35 J.

9. What is the enthalpy of a mixture having 20% of A with enthalpy 20 J, 30% of B with enthalpy 40 J, and 50% of C with enthalpy 20 J?
a) 26 J
b) 29 J
c) 31 J
d) 34 J
View answer

Answer: a
Explanation: Heat capacity of mixture = 0.2*20 + 0.3*40 + 0.5*20 = 26 J.
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10. What is the enthalpy of a mixture having 10% of A with enthalpy 10 J, 30% of B with enthalpy 30 J, and 60% of C with enthalpy 25 J?
a) 21 J
b) 25 J
c) 27 J
d) 28 J
View answer

Answer: b
Explanation: Heat capacity of mixture = 0.1*10 + 0.3*30 + 0.6*25 = 1 + 9 + 15 = 25 J.

11. What is the enthalpy change of solution if the enthalpy change of solute is 10 J, and enthalpy of solvent is 15 J?
a) 10 J
b) 15 J
c) 25 J
d) 40 J
View answer

Answer: c
Explanation: ∆Hsolution = ∆Hsolute +∆Hsolvent = 10 + 15 = 25 J.

12. What is the enthalpy change of 8 mole solution if the enthalpy change of 5 mole solute is 10 J/mole, and enthalpy of 2 mole solvent is 15 J/mole?
a) 10 J/mole
b) 12 J/mole
c) 13 J/mole
d) 15 J/mole
View answer

Answer: a
Explanation: ∆Hsolution = ∆Hsolute +∆Hsolvent, => ∆Hsolution = (10*5 + 15*2)/8 = 10 J/mole.

13. What is the heat evolved when a gaseous solute is mixed with liquid solvent?
a) Heat of solution
b) Heat of mixing
c) Heat of dissolution
d) All of the mentioned
View answer

Answer: a
Explanation: When Gas is mixed with liquid the heat evolved is called heat of solution.

14. What is the heat evolved when a liquid solute is mixed with liquid solvent?
a) Heat of solution
b) Heat of mixing
c) Heat of dissolution
d) All of the mentioned
View answer

Answer: b
Explanation: When liquid is mixed with liquid the heat evolved is called heat of mixing.

15. Heat of solution of a mixture is 10 J, what is the heat dissolution?
a) -10 J
b) 10 J
c) 0
d) Cannot be determined
View answer

Answer: a
Explanation: Heat of dissolution = – Heat of solution = -10 J.

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Manish Bhojasia - Founder & CTO at Sanfoundry
Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He lives in Bangalore, and focuses on development of Linux Kernel, SAN Technologies, Advanced C, Data Structures & Alogrithms. Stay connected with him at LinkedIn.

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