This set of Surveying Multiple Choice Questions & Answers (MCQs) focuses on “Volume Measurement – Curvature Correction”.

1. Which of the following indicates the assumption assumed in case of curvature correction?

a) End sections are parallel

b) End sections are vertical

c) End sections are not present

d) End sections are perpendicular

View Answer

Explanation: The curvature correction is applied in case of prismoidal and trapezoidal formulae. This correction is based on the assumption that the end sections are parallel.

2. Which of the following is not a case assumed in curvature correction?

a) Two level section

b) Three level section

c) Four level section

d) Side hill section

View Answer

Explanation: The curvature correction is applied in case of the prismoidal and the trapezoidal formulae. This correction assumes certain cases like applying it in level-section, two level section, three level section, side hill section.

3. Level section requires application of correction.

a) True

b) False

View Answer

Explanation: The level section one of the cases in the curvature correction. It requires no correction because it involves a symmetrical area about the central line, which makes it free from applying any type of correction.

4. For larger and smaller areas, same formula can be applied in case of side-hill section.

a) False

b) True

View Answer

Explanation: The application of curvature correction requires involves a certain type of cases of which the side hill section has two sub cases. It involves smaller and larger areas. The formula for both differs in case of signs.

5. Correction for curvature is applied for getting ___________

a) Station points

b) Ordinates

c) Heights

d) Equivalent areas

View Answer

Explanation: The correction for curvature can be applied for obtaining the equivalent areas for the type of shape employed for the traverse. It is then followed by the usage of prismoidal formula.

6. What is the correction applied for two-level section if the area of the traverse is 121.45 sq. m and value of e = 9.34?

a) 9.34 sq. m

b) 9.06 sq. m

c) 9.46 sq. m

d) 9.43 sq. m

View Answer

Explanation: The correction applied for two level section can be given as

C = A*e/A, where e is the eccentricity and A is the area. On substitution, we get

C = 121.54 * 9.34 / 121.54 = 9.34 sq. m.

7. What will be the correction for curvature of three level sections, if the areas are given as 43.56 sq. m, 22.54sq.m and h = 56.43 sq. m, b= 2, n= 2 which are having faces at a unity distance having 59.87 m radius?

a) 220.91 sq. m

b) 220.19 sq. m

c) 202.65 sq. m

d) 205.65 sq.m

View Answer

Explanation: The formula of correction for curvature can be given as

C = d*(w

^{2}– w1

^{2})*(h + b/2n) / 6R. On substitution, we get

C = 1*(43.56

^{2}– 22.54

^{2})*(56.43 + 2/2*2) / 6*59.87

C = 220.19 sq. m.

8. Find the value of eccentricity if the values of area of the sides can be given as 134.76 sq. m, 56.76 sq. m and A = 76.65 sq. m with number of sides as 2.

a) 3185.23 sq. m

b) 3158.32 sq. m

c) 3185.32 sq. m

d) 3185.99 sq. m

View Answer

Explanation: The eccentricity value can be given as,

e = w1*w2*(w1+w2) / 3*A*n. on substitution, we get

e = 134.76*56.76*(134.76 + 56.76)/3*76.65*2

e = 3185.32 sq. m.

9. Find the correction for side hill of two level section if the area is given as 654.76 sq. m, and the value of eccentricity is 89.76.

a) 89.76 sq. m

b) 98.76 sq. m

c) 89.67 sq. m

d) 98.54 sq. m

View Answer

Explanation: The correction for the side hill of two level section can be given as

C = A*e / A. On substitution, we get

C = 654.76*89.76 / 654.76

C = 89.76 sq. m.

10. Find the value of e for side hill of small area by using the values provided. W = 54.32 sq. m, b = 1, n = 2, h = 76.24 sq. m.

a) 43.87

b) 87.98

c) 96.1

d) 69.1

View Answer

Explanation: The value of eccentricity for small area can be given as,

e = (w1 + b/2 + n*h) / 3. On substitution, we get

e = 69.1.

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