RDBMS Questions and Answers – SQL Data Definition

This set of RDBMS Multiple Choice Questions & Answers (MCQs) focuses on “SQL Data Definition Problems (Bank Database Schema)”.

Q1) Create a Bank Database schema with the following relations and select an appropriate primary key.
account(account_number, branch_name, balance)
branch (branch_name, branch_city, assets)
customer (customer_name customer_street, customer_city)
loan (loan_number, branch_name, amount)
depositor((customer_name, account_number)
borrower(customer_name, loan_number)
View Answer

Answer: create table account
(account_number varchar(15) not null unique,
branch_name varchar(15) not null,
balance number not null,
primary key(account_number));

create table branch
(branch_name varchar(15) not null unique,
branch_city varchar(15) not null,
assets number not null,
primary key(branch_name));

create table customer
(customer_name varchar(15) not null unique,
customer_street varchar(12) not null,
customer_city varchar(15) not null,
primary key(customer_name));

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create table loan
(loan_number varchar(15) not null unique,
branch_name varchar(15) not null,
amount number not null,
primary key(loan_number));

create table depositor
(customer_name varchar(15) not null,
account_number varchar(15) not null,
primary key(customer_name, account_number),
foreign key(account_number) references account(account_number),
foreign key(customer_name) references customer(customer_name));

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create table borrower
(customer_name varchar(15) not null,
loan_number varchar(15) not null,
primary key(customer_name, loan_number),
foreign key(customer_name) references customer(customer_name),
foreign key(loan_number) references loan(loan_number));

NOTE: Please insert the following data into the database for the execution of further queries.

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insert into customer values (‘Jones’, ‘Main’, ‘Harrison’);
insert into customer values (‘Smith’, ‘Main’, ‘Rye’);
insert into customer values (‘Hayes’, ‘Main’, ‘Harrison’);
insert into customer values (‘Curry’, ‘North’, ‘Rye’);
insert into customer values (‘Lindsay’, ‘Park’, ‘Pittsfield’);
insert into customer values (‘Turner’, ‘Putnam’, ‘Stamford’);
insert into customer values (‘Williams’, ‘Nassau’, ‘Princeton’);
insert into customer values (‘Adams’, ‘Spring’, ‘Pittsfield’);
insert into customer values (‘Johnson’, ‘Alma’, ‘Palo Alto’);
insert into customer values (‘Glenn’, ‘Sand Hill’, ‘Woodside’);
insert into customer values (‘Brooks’, ‘Senator’, ‘Brooklyn’);
insert into customer values (‘Green’, ‘Walnut’, ‘Stamford’);
insert into customer values (‘Jackson’, ‘University’, ‘Salt Lake’);
insert into customer values (‘Majeris’, ‘First’, ‘Rye’);
insert into customer values (‘McBride’, ‘Safety’, ‘Rye’);

insert into branch values (‘Downtown’, ‘Brooklyn’, 900000);
insert into branch values (‘Redwood’, ‘Palo Alto’, 2100000);
insert into branch values (‘Perryridge’, ‘Horseneck’, 1700000);
insert into branch values (‘Mianus’, ‘Horseneck’, 400200);
insert into branch values (‘Round Hill’, ‘Horseneck’, 8000000);
insert into branch values (‘Pownal’, ‘Bennington’, 400000);
insert into branch values (‘North Town’, ‘Rye’, 3700000);
insert into branch values (‘Brighton’, ‘Brooklyn’, 7000000);
insert into branch values (‘Central’, ‘Rye’, 400280);

insert into account values (‘A-101’, ‘Downtown’, 500);
insert into account values (‘A-215’, ‘Mianus’, 700);
insert into account values (‘A-102’, ‘Perryridge’, 400);
insert into account values (‘A-305’, ‘Round Hill’, 350);
insert into account values (‘A-201’, ‘Perryridge’, 900);
insert into account values (‘A-222’, ‘Redwood’, 700);
insert into account values (‘A-217’, ‘Brighton’, 750);
insert into account values (‘A-333’, ‘Central’, 850);
insert into account values (‘A-444’, ‘North Town’, 625);

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insert into depositor values (‘Johnson’,’A-101′);
insert into depositor values (‘Smith’, ‘A-215’);
insert into depositor values (‘Hayes’, ‘A-102’);
insert into depositor values (‘Hayes’, ‘A-101’);
insert into depositor values (‘Turner’, ‘A-305’);
insert into depositor values (‘Johnson’,’A-201′);
insert into depositor values (‘Jones’, ‘A-217’);
insert into depositor values (‘Lindsay’,’A-222′);
insert into depositor values (‘Majeris’,’A-333′);
insert into depositor values (‘Smith’, ‘A-444’);

insert into loan values (‘L-17’, ‘Downtown’, 1000);
insert into loan values (‘L-23’, ‘Redwood’, 2000);
insert into loan values (‘L-15’, ‘Perryridge’, 1500);
insert into loan values (‘L-14’, ‘Downtown’, 1500);
insert into loan values (‘L-93’, ‘Mianus’, 500);
insert into loan values (‘L-11’, ‘Round Hill’, 900);
insert into loan values (‘L-16’, ‘Perryridge’, 1300);
insert into loan values (‘L-20’, ‘North Town’, 7500);
insert into loan values (‘L-21’, ‘Central’, 570);

insert into borrower values (‘Jones’, ‘L-17’);
insert into borrower values (‘Smith’, ‘L-23’);
insert into borrower values (‘Hayes’, ‘L-15’);
insert into borrower values (‘Jackson’, ‘L-14’);
insert into borrower values (‘Curry’, ‘L-93’);
insert into borrower values (‘Smith’, ‘L-11’);
insert into borrower values (‘Williams’,’L-17′);
insert into borrower values (‘Adams’, ‘L-16’);
insert into borrower values (‘McBride’, ‘L-20’);
insert into borrower values (‘Smith’, ‘L-21’);

Sanfoundry Global Education & Learning Series – RDBMS.

To practice all areas of RDBMS, here is complete set of 1000+ Multiple Choice Questions and Answers.

If you find a mistake in question / option / answer, kindly take a screenshot and email to [email protected]

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Manish Bhojasia - Founder & CTO at Sanfoundry
Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He lives in Bangalore, and focuses on development of Linux Kernel, SAN Technologies, Advanced C, Data Structures & Alogrithms. Stay connected with him at LinkedIn.

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