Railway Engineering Questions and Answers – Track Stresses – Coning of Wheels

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This set of Railway Engineering Multiple Choice Questions & Answers (MCQs) focuses on “Track Stresses – Coning of Wheels”.

1. What is the objective of coning of wheels?
a) To save material
b) For easy manufacturing of wheels
c) For easy movement on curves
d) For Aesthetic look
View Answer

Answer: c
Explanation: Rather than making the wheels flat they are sloped like a cone. This is done so that the wheels can traverse curves easily.
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2. What is the value of Slope provided to the wheels?
a) 1 in 30
b) 1 in 20
c) 1 in 40
d) 1 in 15
View Answer

Answer: b
Explanation: The inner diameter of the wheels of the locomotive is greater than the outer diameter. The value of this slope is 1 in 20.

3. What would be the result without coning of wheels?
a) Trains would have travelled slower
b) The flange would have touched the rail
c) Carrying capacity of the train would have reduced
d) Passengers would feel more comfortable
View Answer

Answer: b
Explanation: Without coning of wheels the flat wheels might slip on the tracks during traversing a curve. This would lead to contact of flange and rail track. This would lead to uncomfortable journey.
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4. What is the reason that disables the leading axle to take full advantage of the coning of wheels?
a) Rigidity of the frame
b) Unequal diameter of wheels
c) Sharp curves
d) More speed
View Answer

Answer: a
Explanation: Because of the rigidity of the frame, while moving on a horizontal curve the rear axle moves inwards. Due to this the front axle is unable to take full advantage of coning of wheels.

5. Coning of wheels helps the outer wheel to travel a longer distance than inner wheel.
a) True
b) False
View Answer

Answer: a
Explanation: When the locomotive travels a curve centrifugal force acts on it. Due to this the outer wheel moves outwards and has to travel longer distance as compared to the inner wheel. Thus coning of wheels is done.
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6. Which among the following is the correct formula for calculating the slip?
a) Slip=(2πθ/360)xG
b) Slip=(πθ/360)xG
c) Slip=(4πθ/360)xG
d) Slip=(2πθ/360)xG2
View Answer

Answer: a
Explanation: The slip can be calculated as Slip=(2πθ/360)xG, where G is the gauge in metres. The approximate value of the slip for broad gauge is 0.029 metre per degree of the curve.

Sanfoundry Global Education & Learning Series – Railway Engineering.

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To practice all areas of Railway Engineering, here is complete set of 1000+ Multiple Choice Questions and Answers.

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Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He lives in Bangalore, and focuses on development of Linux Kernel, SAN Technologies, Advanced C, Data Structures & Alogrithms. Stay connected with him at LinkedIn.

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