Python Questions and Answers – Sets – 5

This set of Python Multiple Choice Questions & Answers (MCQs) focuses on “Sets – 5”.

1. What will be the output of the following Python code?

s1={3, 4}
s2={1, 2}
s3=set()
i=0
j=0
for i in s1:
    for j in s2:
        s3.add((i,j))
        i+=1
        j+=1
print(s3)

a) {(3, 4), (1, 2)}
b) Error
c) {(4, 2), (3, 1), (4, 1), (5, 2)}
d) {(3, 1), (4, 2)}
View Answer

2. The ____________ function removes the first element of a set and the last element of a list.
a) remove
b) pop
c) discard
d) dispose
View Answer

3. The difference between the functions discard and remove is that:
a) Discard removes the last element of the set whereas remove removes the first element of the set
b) Discard throws an error if the specified element is not present in the set whereas remove does not throw an error in case of absence of the specified element
c) Remove removes the last element of the set whereas discard removes the first element of the set
d) Remove throws an error if the specified element is not present in the set whereas discard does not throw an error in case of absence of the specified element
View Answer

4. What will be the output of the following Python code?

s1={1, 2, 3}
s2={3, 4, 5, 6}
s1.difference(s2)
s2.difference(s1)

a)

{1, 2}
{4, 5, 6}

b)

{1, 2}
{1, 2}

c)

{4, 5, 6}
{1, 2}

d)

{4, 5, 6}
{4, 5, 6}

5. What will be the output of the following Python code?

s1={1, 2, 3}
s2={4, 5, 6}
s1.isdisjoint(s2)
s2.isdisjoint(s1)

a)

True
False

b)

False 
True

c)

True
True

d)

False
False

6. If we have two sets, s1 and s2, and we want to check if all the elements of s1 are present in s2 or not, we can use the function:
a) s2.issubset(s1)
b) s2.issuperset(s1)
c) s1.issuperset(s2)
d) s1.isset(s2)
View Answer

7. What will be the output of the following Python code?

s1={1, 2, 3, 8}
s2={3, 4, 5, 6}
s1|s2
s1.union(s2)

a)

{3}
{1, 2, 3, 4, 5, 6, 8}

b)

{1, 2, 4, 5, 6, 8}
{1, 2, 4, 5, 6, 8}

c)

{3}
{3}

d)

{1, 2, 3, 4, 5, 6, 8}
{1, 2, 3, 4, 5, 6, 8}

8. What will be the output of the following Python code?

a=set('abc')
b=set('def')
b.intersection_update(a)
a
b

a)

set()
(‘e’, ‘d’, ‘f’}

b)

{}
{}

c)

{‘b’, ‘c’, ‘a’}
set()

d)

set()
set()

9. What will be the output of the following Python code, if s1= {1, 2, 3}?

s1.issubset(s1)

a) True
b) Error
c) No output
d) False
View Answer

10. What will be the output of the following Python code?

x=set('abcde')
y=set('xyzbd')
x.difference_update(y)
x
y

a)

   {‘a’, ‘b’, ‘c’, ‘d’, ‘e’}
   {‘x’, ‘y’, ‘z’}

b)

   {‘a’, ‘c’, ‘e’}
   {‘x’, ‘y’, ‘z’, ‘b’, ‘d’}

c)

   {‘b’, ‘d’}
   {‘b’, ‘d’}

d)

   {‘a’, ‘c’, ‘e’}
   {‘x’, ‘y’, ‘z’}

Sanfoundry Global Education & Learning Series – Python.

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