This is a Python Program to read a number n and print and compute the series “1+2+…+n=”.

The program takes a number n and prints and computes the series “1+2+…+n=”.

1. Take a value from the user and store it in a variable n.

2. Use a for loop where the value of i ranges between the values of 1 and n.

3. Print the value of i and ‘+’ operator while appending the value of i to a list.

4. Then find the sum of elements in the list.

5. Print ‘=’ followed by the total sum.

6. Exit.

Here is the source code of the Python Program to read a number n and print and compute the series “1+2+…+n=”. The program output is also shown below.

n=int(input("Enter a number: ")) a=[] for i in range(1,n+1): print(i,sep=" ",end=" ") if(i<n): print("+",sep=" ",end=" ") a.append(i) print("=",sum(a)) print()

1. User must first enter the value and store it in a variable n.

2. The for loop enables i to range between 1 and n (as n+1 is not included).

3. For each iteration, the value of i is printed.

4. ‘+’ operator is printed only if i

Case 1: Enter a number: 4 1 + 2 + 3 + 4 = 10 Case 2: Enter a number: 5 1 + 2 + 3 + 4 + 5 = 15

**Sanfoundry Global Education & Learning Series – Python Programs.**

To practice all Python programs, __here is complete set of 150+ Python Problems and Solutions__.