# Power Systems Questions and Answers – Symmetrical Component Transformation – 1

This set of Power Systems Multiple Choice Questions & Answers (MCQs) focuses on “Symmetrical Component Transformation – 1”.

1. The receiving end active power for a short transmission line is (where the angles have their usual meanings) 2. The receiving end reactive power for a short transmission line is (where the angles have their usual meanings) 3. The sending end active power for a 20 km transmission line with Vs as the sending end voltage and Vr as receiving end voltage, can be given by most appropriately 4. The sending end reactive power for a 20 km transmission line with Vs as the sending end voltage and Vr as receiving end voltage, can be given by most appropriately 5. The simplified ABCD representation of a 40 km transmission line is best given as Sanfoundry Certification Contest of the Month is Live. 100+ Subjects. Participate Now!

6. For a 35 km transmission line having a lumped impedance of the line as 20 ohms, is required to be shown in the ABCD form, it is given as 7. If it is tried to represent the active and reactive power on a circle, then the radius would be 8. The maximum power delivered to the load for short transmission line is at
a) β=α
b) β>α
c) β=δ
d) β>δ

Explanation: Maximum power occurs for β=δ.

9. The maximum real active power delivered to the load is defined most accurately by 10. For a given power system, its zero and maximum regulation will occur at the impedance angle of
a) 45
b) 90
c) 0
d) 60

Explanation: At θ=45°, ZVR and maximum VR coincide.

11. The charging currents due to shunt admittance can be neglected for ______ transmission line?
a) short
b) long
c) medium
d) all of the mentioned

Explanation: The shun admittance for lines more than 100 km become very prominent and can not be neglected.

12. The transmission line equations are given by the below set of equations based on the line diagram as given. Identify the missing term marked as ’?’.
Vs = ?*Vr+B*Ir
Is = C*Vr+D*Ir a) 1+YZ
b) Z
c) Y
d) 1

Explanation: Using KVL to the line diagram,
Vs = (1+YZ)*Vr+Z*Ir
Is = Y*Vr+Ir.

13. The transmission line equations are given by the below set of equations based on the line diagram as given. Identify the missing term marked as ’?’.
Vs = A*Vr+?*Ir
Is = C*Vr+D*Ir a) 1+YZ
b) Z
c) Y
d) 1

Explanation: Using KVL to the line diagram,
Vs = (1+YZ)*Vr+Z*Ir
Is = Y*Vr+Ir.

14. The transmission line equations are given by the below set of equations based on the line diagram as given. Identify the missing term marked as ’?’.
Vs = A*Vr+B*Ir
Is = ?*Vr+D*Ir a) 1+YZ
b) Z
c) Y
d) 1

Explanation: Using KVL to the line diagram,
Vs = (1+YZ)*Vr+Z*Ir
Is = Y*Vr+Ir.

15. The transmission line equations are given by the below set of equations based on the line diagram as given. Identify the missing term marked as ’?’.
Vs = A*Vr+B*Ir
Is = C*Vr+?*Ir a) 1+YZ
b) Z
c) Y
d) 1

Explanation: Using KVL to the line diagram,
Vs = (1+YZ)*Vr+Z*Ir
Is = Y*Vr+Ir.

Sanfoundry Global Education & Learning Series – Power Systems.

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