This set of Class 11 Physics Chapter 15 Multiple Choice Questions & Answers (MCQs) focuses on “Displacement Relation in a Progressive Wave”.

1. What does the given equation: x = Asin(ky+wt+a) represent?

a) Wave travelling along positive x direction

b) Wave travelling along negative x direction

c) Wave travelling along positive y direction

d) Wave travelling along negative y direction

View Answer

Explanation: A way of looking at a travelling wave is considering the direction in which a particular value of transverse displacement moves. For the given equation x = Asin(ky+wt+a) we have to see the direction in which x moves. For eg: If we consider the amplitude A, for x =A as t increases, y should decrease. So, we can say that the wave propagates in the negative y direction.

2. An equation of a wave is given by: y = 2sin(3x-2t+π/2). What is the minimum distance between two points having the same phase?

a) 3

b) π/2

c) 2π/3

d) π

View Answer

Explanation: In the given equation the phase is 3x-2t+π/2.

This is repeated after every 2π.

∴ sin( 3x-2t+π/2) +2nπ = sin( 3x-2t+π/2).

We can consider the case at t=0, sin(3x+π/2) = sin(3x+π/2+2nπ)

OR cos(3x) = cos(3x+2nπ)

∴ n = 1 for minimum difference.

Minimum distance can be found from kx = 2π

OR x = 2π/k = 2π/3.

3. Consider a sinusoidal wave travelling in the positive x direction. What is the phase difference between the two points shown in the diagram below?

a) 0

b) π

c) π/2

d) 2π

View Answer

Explanation: Let the equation of the wave be y = Asin(kx-wt).

The x coordinate of the two points differs by λ/2.

So, the phase difference will be kλ/2 = (2π/λ)*(λ/2) = π.

An intuitive way to look at this is that both are at their mean positions right now and will be going in opposite directions at the next instant, so we can say they differ by π.

4. A sinusoidal wave has an amplitude of 2cm. It is travelling in the negative x-direction. The distance between two crests is 2cm. The angular frequency is πs^{-1}. What is the displacement of the particle at x = 20.5cm, at t = 10s? Assume that at t=0 & x=0 the particle was at the mean position and going downwards. ‘x’ &’y’ are in cm.

a) 0cm

b) 1cm

c) -1cm

d) -2cm

View Answer

Explanation: The equation suiting the given conditions will be: y = Asin(kx+wt+a)

At x=0, t=0, velocity is negative, so ‘a’ will be π.

k = 2π/λ = π.

∴ y = 2sin(πx + 2t + π).

At x=20cm & t=10s,

y = 2sin(20.5π + 10π + π)

= 2sin(31.5π)

= -2cm.

5. The equation of a wave is given by y = 3sin(4x-2t). What is the time period and wavelength of the wave?

a) T = 2π, λ = 2π

b) T = π, λ = 2π

c) T = π, λ = π/2

d) T = π/2, λ = π

View Answer

Explanation: From the equation we get: k=4 & w=2.

Wavelength is given by 2π/k = 2π/4 = π/2.

Time period = 2π/w

= 2π/2 = π.

6. A sinusoidal wave has an amplitude of 3cm. Time period is 1s. The wavelength is 1cm. And at x = 0, t=0 the particle is at its mean position & moving upwards. What is the equation of the wave if it is travelling along the positive x-axis?

a) y = 3sin(2πx – 2πt)

b) y = 3sin(2πt – 2πx)

c) x = 3sin(2πt – 2πy)

d) y = 3cos(π + 2πt – 2πx)

View Answer

Explanation: The wave number k = 2π/1 = 2π.

The angular frequency w = 2π/1 = 2π.

The particle at x=0, t=0 is moving up from its mean position, & the wave travels towards the positive x-axis so the equation will be:

y = 3sin(2πt – 2πx).

**Sanfoundry Global Education & Learning Series – Physics – Class 11**.

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