Physics Questions and Answers – Motion in a Plane with Constant Acceleration

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This set of Physics Multiple Choice Questions & Answers (MCQs) focuses on “Motion in a Plane with Constant Acceleration”.

1. The velocity of a body, moving in a plane, changes from 3î to 3î + 7ĵ in 10s. What is the acceleration of the body?
a) 0.7ĵ
b) 0.7î
c) 0.33î + 7ĵ
d) 0.3î + 7ĵ
View Answer

Answer: a
Explanation: The acceleration of a body is the rate at which the velocity changes with time. Here, the change in velocity is 7ĵ. The total time taken is 10s. Hence, the acceleration = change in velocity/time = 0.7ĵ.
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2. The position of a body, moving in a plane, changes from origin to 14î + 11ĵ in 20s. What is the velocity of the body?
a) 0.7î + 0.55ĵ
b) 0.55î + 0.7ĵ
c) 0.3î + 0.7ĵ
d) 0.3î
View Answer

Answer: a
Explanation: The velocity of a body is the rate at which the displacement changes with time. Here, the change in position is the change in displacement, and is 14î + 11ĵ. The total time taken is 20s. Hence, the acceleration = change in displacement/time = 0.7î + 0.55ĵ.

3. A car moves 25 units in the positive X direction and 75 units in negative Y direction starting from the origin in 25 seconds. What is the velocity vector of the car?
a) î – 3ĵ
b) 3î – ĵ
c) î + 3ĵ
d) 3î + ĵ
View Answer

Answer: a
Explanation: The initial position of the car is at the origin and the final position is 25î – 75ĵ. Hence the displacement is 25î – 75ĵ. The total time taken is 25 s. Hence, the velocity = change in position/time = î – 3ĵ.
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4. A body moves from point A (3,6) to point B (11,12) to point C (15,15). What is the average speed of the body along the given path if the total time taken is 100s?
a) 0.15 units/s
b) 1.5 units/s
c) 15 units/s
d) 0.0015 units/s
View Answer

Answer: a
Explanation: The distance between A and B is 10 units. The distance between B and C is 5 units. Hence, the total distance is 15 units. The total time taken is 100 s. Average speed = total distance/total time taken = 15/100 = 0.15 units/s.

5. A body moves from point A (2,1) to point B (7,13) to point C (15,19). What is the average speed of the body along the given path if the total time taken is 20 s?
a) 1.15 units/s
b) 11.5 units/s
c) 115 units/s
d) 0.0115 units/s
View Answer

Answer: a
Explanation: The distance between A and B is 13 units. The distance between B and C is 10 units. Hence, the total distance is 23 units. The total time taken is 20 s. Average speed = total distance/total time taken = 23/20 = 1.15 units/s.
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6. A body is moving with a constant acceleration of 11î + 7ĵ, starting from the origin. What will be the position of the body after 10s?
a) 550î + 350ĵ
b) 350î + 550ĵ
c) 350î – 550ĵ
d) 550î – 350ĵ
View Answer

Answer: a
Explanation: The body’s displacement is given by s = (1/2)at2. The body starts from the origin hence, the total displacement is the final position of the body. Therefore, after putting in the values, we get, s = (1/2)(11î + 7ĵ)*102 = 550î + 350ĵ.

7. Which of the following is an example of uniformly accelerated motion in a plane?
a) Motion of a particle in a plane
b) Motion of a particle in a circle
c) Motion of a pendulum
d) Motion of a spring
View Answer

Answer: a
Explanation: From the given options, the only motion that can possibly have a uniformly accelerated motion in a plane is that of a particle. In circular motion the direction of the acceleration keeps changing and in a pendulum and in a spring, both the magnitude and directions keep changing.
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Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He is Linux Kernel Developer & SAN Architect and is passionate about competency developments in these areas. He lives in Bangalore and delivers focused training sessions to IT professionals in Linux Kernel, Linux Debugging, Linux Device Drivers, Linux Networking, Linux Storage, Advanced C Programming, SAN Storage Technologies, SCSI Internals & Storage Protocols such as iSCSI & Fiber Channel. Stay connected with him @ LinkedIn | Youtube | Instagram | Facebook | Twitter