Class 11 Physics MCQ – Thermal Properties of Matter

This set of Class 11 Physics Chapter 11 Multiple Choice Questions & Answers (MCQs) focuses on “Thermal Properties of Matter”. These MCQs are created based on the latest CBSE syllabus and the NCERT curriculum, offering valuable assistance for exam preparation.

1. Boyle’s and Charle’s law are obeyed by low density gases only. True or False?
a) True
b) False
View Answer

Answer: a
Explanation: Boyle’s and Charle’s law are used to arrive at the ideal gas law. And the ideal gas law is based on the assumptions of kinetic theory of gases, which are only valid for low density gases. For eg: the assumption that molecules exert no forces on each other can only be considered for low density.

2. Boyle’s law and Charle’s law together form which law?
a) PV/T = constant
b) PV2/T = constant
c) PV = constant
d) V/T = constant
View Answer

Answer: a
Explanation: Boyle’s law states that P ∝ 1/V.
Charle’s law states that V ∝ T.
From this we can say that
V ∝ T/P OR PV/T = constant.
Note that this is the ideal gas law.

3. Why can any low density gas be used in a constant volume gas thermometer?
a) All low density gases show the same expansion behaviour
b) They are easy to handle
c) Their pressure variation is proportional to square of the change in temperature
d) The given statement is not true
View Answer

Answer: a
Explanation: It has been experimentally shown that low density gases show similar expansion behaviour. If we keep the gas’s volume constant pressure increases monotonically with increasing temperature. Hence, we can use any low density gas for a constant volume gas thermometer.

4. For a constant volume gas thermometer select the correct statement.
a) It doesn’t use mercury for pressure measurement
b) We actually measure the pressure at constant volume and the scale is calibrated to give the temperature reading
c) Any high density gas can be used
d) Pressure ∝ Temp2
View Answer

Answer: b
Explanation: A constant volume gas thermometer has a mercury manometer connected to a gas bulb. With increase in temperature of the bulb, its volume is kept constant by external methods and the pressure of gas increases. The temperature scale is defined as a function of this pressure. (T = kP, where k is a constant).

5. What is absolute zero?
a) It is the minimum temperature that has been achieved
b) It is the lowest temperature of air
c) It is -273K
d) It is the temperature at which an ideal gas will have zero pressure, assuming it stays a gas
View Answer

Answer: d
Explanation: Absolute zero has been defined as the temperature at which an ideal gas would have zero pressure, assuming it remains a gas till then. The temperature value is obtained by extrapolating the graph of Pressure vs Temperature till the straight line cuts the temperature axis. This gives us a value of -273.15°C. Note that this temperature hasn’t been achieved yet.

6. What is considered as zero point on the Kelvin scale?
a) -273.15K
b) -273.15°C
c) 0°C
d) -273.15°C
View Answer

Answer: b
Explanation: Zero point on the kelvin scale is absolute zero point.
This corresponds to the temperature of -273.15°C.
Also note that the kelvin scale and celsius scale have the same size of unit,
so K = 273.15 + °C.

7. What is the value of gas constant?
a) 8.314 kJ mol-1K-1
b) 8.314 L atm mol-1K-1
c) 0.0821 L atm mol-1K-1
d) It is equal to the constant in PV/T = constant
View Answer

Answer: c
Explanation: The value of universal gas constant is 0.0821 L atm mol-1K-1.
Or it is 8.314 J mol-1K-1.
The constant in PV/T = constant depends on the number of moles taken.

8. In a constant volume gas thermometer, the pressure of liquid, at a temperature of 27°C, being measured corresponds to 50cm of mercury. If the temperature increases by 20K, find the pressure.
a) 53.33cm
b) 87.03cm
c) 65.33cm
d) 97.03cm
View Answer

Answer: a
Explanation: For a constant volume gas thermometer, P/T = constant.
P1/T1 = P2/T2
∴ P2 = P1/T1 * T2 = 50/300 * 320 = 53.33cm.

More MCQs on Class 11 Physics Chapter 11:


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