This set of Numerical Analysis Multiple Choice Questions & Answers (MCQs) focuses on “Regula Falsi Method”.

1. The formula used for solving the equation using Regula Falsi method is x = \(\frac{bf(a)-af(b)}{f(a)-f(b)}\).

a) True

b) False

View Answer

Explanation: Let there be two point a and b between which the root lies.

The slope can be written as

\(\frac{y-f(a)}{x-a}=\frac{f(a)-f(b)}{a-b}\)

let y = f(x) = 0

\(\frac{-f(a)}{x-a}=\frac{f(a)-f(b)}{a-b} \)

Therefore,

x = \(\frac{bf(a)-af(b)}{f(a)-f(b)}\).

2. Find the positive root of the equation 3x-cosx-1 using Regula Falsi method and correct upto 4 decimal places.

a) 0.6701

b) 0.5071

c) 0.6071

d) 0.5701

View Answer

Explanation: f(0) = -2

f(1) = 1.459697694

Therefore the root lies between 0 and 1 and

a = 0; f(a) = -2

b = 1; f(b) = 1.459697694

Substituting the values in the formula,

x = \(\frac{bf(a)-af(b)}{f(a)-f(b)}\),

we get \(x1 = \frac{-2-0}{-2-1.459697694}\)=0.57808519; f(x1) = -0.103254906

Therefore, x1 becomes a to find the next point.

\(X2 =\frac{-0.103254906-(0.57808519)(1.459697694)}{-0.103254906-1.459697694}\)= 0.604952253; f(x2) = -7.67249301*10

^{-3}

Therefore, x2 becomes a to find the next point.

\(X3 =\frac{(-7.67249301*10^{-3}-(0.604952253)(1.459697694)}{(-7.67249301*10^{-3})-1.459697694}\) = 0.607017853; f(x3) = -2.991836798*10

^{-4}

Therefore, x3 becomes a to find the next point.

\(X4 =\frac{(-2.991836798*10^{-4})-(0.607017853)(1.459697694)}{(-2.991836798*10^{-4} )-1.459697694}\) =0.607098383; f(x4) = -1.165728726*10

^{-5}

Therefore, x4 becomes a to find the next point.

\(X5 = \frac{(-1.165728726*10^{-5})-(0.607098383)1.459697694}{(-1.165728726*10^{-5} )-1.459697694}\)=0.60710152; f(x5) = -4.54801046*10

^{-7}

Therefore x5 becomes a to find the next point.

\(X6 =\frac{(-4.54801046*10^{-7})-(0.60710152)(1.459697694)}{(-4.54801046*10^{-7} )-1.459697694}]\)= 0.607101642

Therefore, the positive root corrected to 4 decimal places is 0.6071.

3. Find the positive root of the equation x^{3} + 2x^{2} + 10x – 20 using Regula Falsi method and correct upto 4 decimal places.

a) 1.3688

b) 1.3866

c) 1.4688

d) 1.6488

View Answer

Explanation: f(1) = -7

f(2) = 16

Therefore, root lies between 1 and 2

a = 1; f(a) = -7

b = 2; f(b) = 16

Substituting the values in the formula,

x = \(\frac{bf(a)-af(b)}{f(a)-f(b)}\),

we get \(x1 = \frac{2(-7)-16}{-7-16}\)=1.304347826; f(x1) = -1.334757952

Therefore, x1 becomes a to find the next point.

\(X2 =\frac{2(-1.334757952)-(1.304347826)16}{-1.334757952-16}\)= 1.357912305; f(x2) = -0.229135731

Therefore, x2 becomes a to find the next point.

\(X3 = \frac{2(-0.229135731)-(1.357912305)16}{-0.229135731-16}\)=1.366977805; f(x3) = -0.038591868

Therefore, x3 becomes a to find the next point.

\(X4 = \frac{2(-0.038591868)-16(1.366977805)}{-0.038591868-16}\)=1.368500975; f(x4) = -6.478731338*10

^{-3}

Therefore, x4 becomes a to find the next point.

\(X5 =\frac{2(-6.478731338*10^{-3})-16(1.368500975)}{(-6.478731338*10^{-3})-16}\)= 1.368756579; f(x5) = -1.087052822 * 10

^{-3}

Therefore x5 becomes a to find the next point.

\(X6 = \frac{2(-1.087052822*10^{-3})-16(1.368756579)}{(-1.087052822*10^{-3})-16}\)=1.368799463; f(x6) = -1.823661977*10

^{-4}

Therefore x6 becomes a to find the next point.

\(X7 = \frac{2(-1.823661977*10^{-4})-16(1.368799463)}{(-1.823661977*10^{-4})-16}\)=1.368806657; f(x7) = -3.0601008*10

^{-5}

Therefore x7 becomes a to find the next point.

\(X8 = \frac{2(-3.0601008*10^{-5})-1.368806657(16)}{(-3.0601008*10^{-5})-16}\)=1.368807864.

Therefore, the positive root corrected to 4 decimal places is 1.3688.

4. Find the positive root of the equation 3x+sinx-e^{x} using Regula Falsi method and correct upto 4 decimal places.

a) 0.4604

b) 0.4306

c) 0.3604

d) 0.4304

View Answer

Explanation: f(0) = -1

f(1) = 1.123189156

Therefore, root lies between 0 and 1

a = 0; f(a) = -1

b = 1; f(b) = 1.123189156

Substituting the values in the formula,

x = \(\frac{bf(a)-af(b)}{f(a)-f(b)} \),

we get \(x1 = \frac{-1}{-1-1.123189156}\)=0.470989594; f(x1) = 0.265158816

Therefore, x1 becomes b to find the next point.

\(X2 = \frac{-0.470989594}{-1-0.265158816}\)=0.372277051; f(x2) = 0.029533668

Therefore, x2 becomes b to find the next point.

\(X3 = \frac{-0.029533668}{-0.029533668-1}\)=0.361597743; f(x3) = 2.940998193*10-3

Therefore, x3 becomes b to find the next point.

\(X4 = \frac{-0.361597743}{-1-(2.940998193*10^{-3})}\)=0.360537403; f(x4) = 2.89448416*10

^{-3}

Therefore, x4 becomes b to find the next point.

\(X5 =\frac{-0.360537403}{-1-(2.89448416*10^{-3})}\)=0.360433076; f(x5) = 2.84536596 * 10

^{-5}

Therefore x5 becomes b to find the next point.

\(X6 = \frac{-0.360433076}{-1-(2.84536596*10^{-5})}\)=0.36042282

Therefore, the positive root corrected to 4 decimal places is 0.3604.

5. Find the positive root of the equation x-cosx using Regula Falsi method and correct to 4 decimal places.

a) 0.73908

b) 0.63908

c) 0.74980

d) 0.64908

View Answer

Explanation: f(0) = -1

f(1) = 0.459697694

Therefore, root lies between 0 and 1

a = 0; f(a) = -1

b = 1; f(b) = 0.459697694

Substituting the values in the formula,

x = \(\frac{bf(a)-af(b)}{f(a)-f(b)}\),

we get \(x1 = \frac{-1}{-1-0.459697694}\)=0.685073357; f(x1) = -0.089299276

Therefore, x1 becomes a to find the next point.

\(X2 =\frac{-0.089299276-0.685073357(0.459697694)}{-0.089299276-0.459697694} \)= 0.736298997; f(x2) = -4.66039555*10

^{-3}

Therefore, x2 becomes a to find the next point.

\(X3 = \frac{-(-4.66039555*10^{-3})-0.736298997(0.459697694)}{(-4.66039555*10^{-3})-0.459697694}\)=0.738945355; f(x3) = -2.339261948*10

^{-4}

Therefore, x3 becomes a to find the next point.

\(X4 = \frac{(-2.339261948*10^{-4})-0.738945355(0.459697694)}{(-2.339261948*10^{-4})-0.459697694}\)=0.73907813; f(x4) = -1.172028721*10

^{-5}

Therefore, x4 becomes a to find the next point.

\(X5 = \frac{-(1.172028721*10^{-5})-0.73907813(0.459697694)}{(-1.172028721*10^{-5} )-0.459697694}\)=0.739084782

Therefore, the positive root corrected to 4 decimal places is 0.73908.

6. Find the positive root of the equation xe^{x}-3 using Regula Falsi method and correct to 4 decimal places.

a) 1.0498

b) 1.4089

c) 2.0489

d) 2.4089

View Answer

Explanation: f(1) = -0.281718171

f(2) = 11.7781122

Therefore, root lies between 1 and 2

a = 1; f(a) = -0.281718171

b = 2; f(b) = 11.7781122

Substituting the values in the formula,

x = \(\frac{bf(a)-af(b)}{f(a)-f(b)}\),

we get \(x1 = \frac{2(-0.281718171)-11.7781122}{-0.281718171-11.7781122}\)=1.023360044; f(x1) = -0.152471518

Therefore, x1 becomes a to find the next point.

\(X2 = \frac{2(-0.152471518)-1.023360044(11.7781122)}{-0.152471518-11.7781122}\)=1.03584141; f(x2) = -0.081541799

Therefore, x2 becomes a to find the next point.

\(X3 = \frac{2(-0.081541799)-1.03584141(11.7781122)}{-0.081541799-11.7781122}\)=1.042470543; f(x3) = -0.043329034

Therefore, x3 becomes a to find the next point.

\(X4 = \frac{2(-0.043329034)-1.042470543(11.7781122)}{-0.043329034-11.7781122}\)=1.045980168; f(x4) = -0.022944949

Therefore, x4 becomes a to find the next point.

\(X5 = \frac{2(-0.022944949)-1.045980168(11.7781122)}{-0.022944949-11.7781122}\)=1.047835063; f(x5) = -0.012128518

Therefore x5 becomes a to find the next point.

\(X6 = \frac{2(-0.012128518)-1.047835063(11.7781122)}{-0.012128518-11.7781122}\)=1.048809506; f(x6) = -6.43428458*10

^{-3}

Therefore x6 becomes a to find the next point.

\(X7 = \frac{2(-6.43428458*10^{-3})-1.048809506(11.7781122)}{-(6.43428458*10^{-3} )-11.7781122}\)=1.04932885; f(x7) = -3.396085929*10

^{-3}

Therefore x7 becomes a to find the next point.

\(X8 = \frac{2(-3.396085929*10^{-3})-1.04932885(11.7781122)}{(-3.396085929*10^{-3} )-11.7781122}\)= 1.049602886; f(x8) = -1.792004364*10

^{-3}

Therefore x8 becomes a to find the next point.

\(X9 = \frac{2(-1.792004364*10^{-3})-1.049602886(11.7781122)}{(-1.792004364*10^{-3} )-11.7781122}\)=1.049773434; f(x9)=-7.933671744 * 10

^{-4}

Therefore x9 becomes a to find the next point.

\(X10 = \frac{2(-7.933671744*10^{-4})-(1.049773434)11.7781122}{(-7.933671744*10^{-4} )-11.7781122}\) = 1.049837436.

Therefore, the positive root corrected to 4 decimal places is 1.0498.

7. Find the positive root of the equation 4x = e^{x} using Regula Falsi method and correct to 4 decimal places.

a) 0.5374

b) 0.3574

c) 0.3647

d) 0.4673

View Answer

Explanation: f(0) = -1

f(1) = 1.281718172

Therefore, root lies between 0 and 1

a = 0; f(a) = -1

b = 1; f(b) = 1.281718172

Substituting the values in the formula,

x = \(\frac{bf(a)-af(b)}{f(a)-f(b)} \),

we get \(x1 = \frac{-1}{-1-1.281718172}\)=0.43826622; f(x1) = 0.203047383

Therefore, x1 becomes b to find the next point.

\(X2 = \frac{0.43826622}{-1-0.203047383} \)= 0.364296723; f(x2) = 0.017685609

Therefore, x2 becomes b to find the next point.

\(X3 = \frac{-0.364296723}{-1-0.017685609}\)=0.357965878; f(x3) = 1.446702162*10

^{-3}

Therefore, x3 becomes b to find the next point.

\(X4 = \frac{-0.357965878}{-1-(1.446702162*10^{-3})}\)=0.357448756; f(x4) = 1.177221*10

^{-4}

Therefore, x4 becomes b to find the next point.

\(X5 = \frac{-0.357448756}{-1-(1.177221*10^{-4})}\)= 0.357406681

Therefore, the positive root corrected to 4 decimal places is 0.3574.

8. Find the positive root of the equation xlogx = 1.2 using Regula Falsi method and correct to 4 decimal places.

a) 2.7406

b) 2.4760

c) 2.5760

d) 2.4706

View Answer

Explanation: f(2) = -0.597940008

f(3) = 0.231363764

Therefore, root lies between 2 and 3

a = 2; f(a) = -0.597940008

b = 3; f(b) = 0.231363764

Substituting the values in the formula,

x = \(\frac{bf(a)-af(b)}{f(a)-f(b)}\),

we get \(x1 = \frac{3(-0.597940008)-2(0.231363764)}{-0.597940008-0.231363764}\)=2.721014456; f(x1) = -0.017091075

Therefore, x1 becomes a to find the next point.

\(X2 = \frac{3(-0.017091075)-2.721014456(0.231363764)}{-0.017091075-0.231363764}\)=2.740205722; f(x2) = -3.840558354*10

^{-4}

Therefore, x2 becomes a to find the next point.

\(X3 = \frac{3(-3.840558354*10^{-4})-2.740205722(0.231363764)}{(-3.840558354*10^{-4})-0.231363764)}\)=2.740636257; f(x3) = -8.58117537*10

^{-6}

Therefore, x3 becomes a to find the next point.

\(X4 = \frac{3(-8.58117537*10^{-6})-(2.740636257)0.231363764}{(-8.58117537*10^{-6})-0.231363764}\)=2.740645876.

Therefore, the positive root corrected to 4 decimal places is 2.7406.

9. Find the positive root of the equation e^{-x} = sinx using Regula Falsi method and correct upto 4 decimal places.

a) 0.5855

b) 0.6685

c) 0.5885

d) 0.6885

View Answer

Explanation: f(0) = 1

f(1) = -0.473591543

Therefore, root lies between 0 and 1

a = 0; f(a) = 1

b = 1; f(b) = -0.473591543

Substituting the values in the formula,

x = \(\frac{bf(a)-af(b)}{f(a)-f(b)}\),

we get \(x1 = \frac{1}{1+0.473591543}\)=0.954782316; f(x1) = -0.431292064

Therefore, x1 becomes b to find the next point.

\(X2 = \frac{0.954782316}{1+0.431292064}\)0.667077209; f(x2) = -0.105486008

Therefore, x2 becomes b to find the next point.

\(X3 = \frac{0.667077209}{1+0.105486008}\)= 0.60342438; f(x3) = -0.020529909

Therefore, x3 becomes b to find the next point.

\(X4 = \frac{0.60342438}{1+0.020529909}\)=0.591285345; f(x4) = -3.813368755*10

^{-3}

Therefore, x4 becomes b to find the next point.

\(X5 = \frac{0.591285345}{1+(3.813368755*10^{-3})}\)=0.589039121; f(x5) = -7.021514375*10

^{-4}

Therefore x5 becomes b to find the next point.

\(X6 = \frac{0.589039121}{1+(7.021514375*10^{-4})}\)=0.588625816; f(x6) = -1.29077269*10

^{-4}

Therefore x6 becomes b to find the next point.

\(X7 = \frac{0.588625816}{1+(1.29077269*10^{-4})}\)= 0.588549847; f(x7) = -2.372079757*10

^{-5}

Therefore x7 becomes b to find the next point.

\(X8 = \frac{0.588549847}{1+(2.372079757*10^{-5})}\)=0.588535886.

Therefore, the positive root corrected to 4 decimal places is 0.5885.

10. Find the positive root of the equation x^{3} + 2x^{2} + 50x + 7 = 0 using Regula Falsi method and correct to 4 decimal places.

a) 0.14073652

b) 0.24073652

c) 0.42076352

d) doesn’t have any positive root

View Answer

Explanation: The given equation doesn’t have any positive root as there is no sign change for any positive integer.

11. Find the positive root of the equation x^{3} – 4x – 9 = 0 using Regula Falsi method and correct to 4 decimal places.

a) 2.6570

b) 2.7605

c) 2.7506

d) 2.7065

View Answer

Explanation: f(2) = -9

f(3) = 6

Therefore, root lies between 2 and 3

a = 2; f(a) = -9

b = 3; f(b) = 6

Substituting the values in the formula,

\(x = \frac{bf(a)-af(b)}{f(a)-f(b)}\),

we get \(x1 = \frac{3(-9)-2(6)}{-9-6}\)=2.6; f(x1) = -1.824

Therefore, x1 becomes a to find the next point.

\(X2 =\frac{3(-1.824)-2.6(6)}{-1.824-6}\)= 2.693251534; f(x2) = -0.23722651

Therefore, x2 becomes a to find the next point.

\(X3 = \frac{3(-0.23722651)-2.693251534(6)}{-0.23722651-6}\)=2.704918397; f(x3) = -0.028912179

Therefore, x3 becomes a to find the next point.

\(X4 = \frac{3(-0.028912179)-2.704918397(6)}{-0.028912179-6}\)=2.70633487; f(x4) = -3.495420729*10

^{-3}

Therefore, x4 becomes a to find the next point.

\(X5 = \frac{3(-3.495420729*10^{-3})-2.70633487(6)}{(-3.495420729*10^{-3})-6}\)=2.706505851; f(x5) = -3.973272762*10

^{-4}

Therefore x5 becomes a to find the next point.

\(X6 = \frac{3(-3.973272762*10^{-4})-2.706505851(6)}{(-3.973272762*20^{-4})-6}\)=2.706525285.

Therefore, the positive root corrected to 4 decimal places is 2.7065.

12. Find the positive root of the equation x^{3} – 4x + 9 = 0 using Regula Falsi method and correct to 4 decimal places.

a) 3.706698931

b) 2.706698931

c) 3.076698931

d) no positive roots

View Answer

Explanation: The given equation doesn’t have any positive root ass there is no sign change for any positive values.

13. Find the positive root of the equation e^{x} = 3x using Regula Falsi method and correct to 4 places.

a) 0.6190

b) 0.7091

c) 0.7901

d) 0.6910

View Answer

Explanation: f(0) = 1

f(1) = -0.281718171

Therefore, root lies between 0 and 1

a = 0; f(a) = 1

b = 1; f(b) = -0.281718171

Substituting the values in the formula,

x = \(\frac{bf(a)-af(b)}{f(a)-f(b)}\),

we get \(x1 = \frac{1}{1+0.281718171}\)=0.780202717; f(x1) = -0.158693619

Therefore, x1 becomes b to find the next point.

\(X2 = \frac{0.780202717}{1+0.158693619}\)=0.673346865; f(x2) = -0.059251749

Therefore, x2 becomes b to find the next point.

\(X3 = \frac{0.673346865}{1+0.059251749}\)=0.635681617; f(x3) = -0.018736045

Therefore, x3 becomes b to find the next point.

\(X4 = \frac{0.635691617}{1+0.018736045}\)=0.623990502; f(x4) = -5.610588465*10

^{-3}

Therefore, x4 becomes b to find the next point.

\(X5 = \frac{0.623990502}{1+(5.610588465*10^{-3})}\)=0.62050908; f(x5) = -1.652615179*10

^{-3}

Therefore x5 becomes b to find the next point.

\(X6 = \frac{0.62050908}{1+(1.652615179*10^{-3})}\)=0.619485309; f(x6) = -4.844127073*10

^{-4}

Therefore x6 becomes b to find the next point.

\(X7 = \frac{0.619485309}{1+(4.844127073*10^{-4})}\)= 0.619195367; f(x7) = -1.417874765*10

^{-4}

Therefore x7 becomes b to find the next point.

\(X8 = \frac{0.619195367}{1+(1.417874765*10^{-4})}\)=0.619097586; f(x8) = -4.14829789*10

^{-5}

Therefre x8 becomes b to find the next point.

\(X9 = \frac{0.619097586}{1+(4.14828789*10^{-5})}\)=0.619071905

Therefore, the positive root corrected to 4 decimal places is 0.6190.

**Sanfoundry Global Education & Learning Series – Numerical Methods.**

To practice all areas of Numerical Methods, __here is complete set of 1000+ Multiple Choice Questions and Answers__.

**If you find a mistake in question / option / answer, kindly take a screenshot and email to [email protected]**

**Related Posts:**

- Practice Probability and Statistics MCQ
- Practice Engineering Mathematics MCQ
- Apply for 1st Year Engineering Internship
- Check Numerical Methods Books