Networking Questions and Answers – IP Addressing

This set of Network Security Interview Questions and Answers for experienced focuses on “IP Addressing”.

1. Convert the following binary notation to dotted-decimal notation –
10000000 00001011 00000011 00011111
a) 128.11.5.32
b) 128.11.3.31
c) 127.11.3.32
d) 127.12.5.31
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2. Convert the following binary notation to hexadecimal notation –
10000000 00001011 00000011 00011111
a) 0x 80 0B 03 1E
b) 0x 81 0B 04 1E
c) 0x 80 0C 03 1F
d) 0x 80 0B 03 1F
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3. Convert the following binary notation to dotted-decimal notation –
10000001 00001011 00001011 11101111
a) 129.11.11.239
b) 128.11.12.231
c) 127.11.13.244
d) 129.12.1.231
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4. Convert the following dotted-decimal notation to binary notation – 111.56.45.78
a) 01101111 00111000 00101101 01001110
b) 11101111 00111000 00101101 10001110
c) 10000000 00001011 00000011 00011111
d) 10000001 00001011 00001011 11101111
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5. What is the error (if any) in the following representation – 111.56.045.78?
a) There should be no leading zeros
b) We cannot have more than 4 bytes in an IPv4 address
c) Each byte should be less than or equal to 255
d) No error
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6. What is the error (if any) in the following representation – 221.34.7.8.20?
a) There should be no leading zeros
b) Each byte should be less than or equal to 255
c) We cannot have more than 4 bytes in an IPv4 address
d) No error
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7. What is the error (if any) in the following representation – 75.45.301.14?
a) There should be no leading zeros
b) We cannot have more than 4 bytes in an IPv4 address
c) Each byte should be less than or equal to 255
d) No error
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8. What is the error (if any) in the following representation – 11100010.23.14.67?
a) There should be no leading zeros
b) We cannot have more than 4 bytes in an IPv4 address
c) Each byte should be less than or equal to 255
d) None of the mentioned
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9. The following IPv4 addresses in hexadecimal notation is – 10000001 00001011 00001011 11101111-
a) 0x810B0BEF
b) 0x810D0AFF
c) 0x810B0BFE
d) 0x810C0CEF
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10. Find the number of addresses in a range if the first address is 146.102.29.0 and last address is 146.102.32.255.
a) 1028
b) 1024
c) 578
d) 512
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11. The first address in a range of addresses is 14.11.45.96. If the number of addresses in the range is 32, what is the last address?
a) 14.11.44.64
b) 14.11.44.128
c) 14.12.44.128
d) 14.11.45.127
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