Machine Tools Questions and Answers – Numericals on Drilling Machine – 1

This set of Machine Tools Multiple Choice Questions & Answers (MCQs) focuses on “Drilling Operation-1”.

1. A hole is being drilled with 5 mm drill at a feed of 0.1 mm/revolution and rpm is 200. Calculate the metal removal rate (m) in mm3/minute.
a) 392.5
b) 785
c) 1570
d) none of the mentioned
View Answer

Answer: a
Explanation: Here, we have the value of diameter, feed and rpm. So, from the formula, m= ( 3.14*d*d*f*n) / 4, we can easily get the value of metal removal rate.

2. If drill is 2.5 mm, feed is 0.35 mm/revolution and metal removal rate is 40 mm3/minute. Then find out the value of rpm.
a) 46.6
b) 23.3
c) 93.2
d) 11.65
View Answer

Answer: b
Explanation: From the formula, m= ( 3.14*d*d*f*n) / 4. From this formula, we can easily calculate rpm. Rpm means revolution per minute.

3. If drill is 5.5 mm, metal removal rate is 65 mm3/minute and rpm is 130.Then find the value of feed in mm/revolution.
a) 0.02
b) 0.2
c) 0.04
d) 0.4
View Answer

Answer: a
Explanation: Feed is the distance the drill moves into the work at each revolution of the spindle. From the formula, m= ( 3.14*d*d*f*n) / 4, we can easily calculate feed.
advertisement
advertisement

4. If metal removal rate is 120 mm3/minute, rpm is 105 and feed is 0.1 mm/revolution. Then find the value of drill in mm.
a) 14.6
b) 3.8
c) 7.6
d) 1.9
View Answer

Answer: b
Explanation: From the formula, m= ( 3.14*d*d*f*n) / 4, we can calculate the value of drill.

5. If value of the diameter of the drill (d2) = 10mm, then find the value of the depth of cut (d1).
a) 5
b) 10
c) 20
d) none of the mentioned
View Answer

Answer: a
Explanation: Value of diameter of the drill is always twice to that the value of the depth of cut. From the formula, d1= d2/2.
Note: Join free Sanfoundry classes at Telegram or Youtube

6. The diameter of the drill is 15 mm and rpm of drill is 5. Find the value of cutting speed in meter/minute.
a) 235.5
b) 0.2355
c) 0.075
d) 75
View Answer

Answer: b
Explanation: From the formula, cs = (3.14*d*n) /1000. Cutting speed is the peripheral speed of the drill.

7. Rpm is 10 and feed per revolution (f2) is 5. Then find the value of feed per minute (f1).
a) 2
b) 4
c) 1
d) none of the mentioned
View Answer

Answer: d
Explanation: Rpm = f1/f2. Here rpm=10 and f2=5. So value of f1 should be 50.
advertisement

8. If depth of cut is 20 mm, then find the value of diameter of the drill.
a) 10
b) 20
c) 40
d) none of the mentioned
View Answer

Answer: c
Explanation: Depth of cut=diameter/2. It is simply a distance.

9. Feed per minute (f1) is 20 and rpm (n) is 5. Then find the value of feed per revolution (f2).
a) 2
b) 4
c) 1
d) 0.5
View Answer

Answer: b
Explanation: Rpm = f1/f2. Here f1=20 and n=5. So, f2 should be 4.
advertisement

10. If t=2minute, n=2rpm and s=5 mm. Then find the value of l. t=machining time in minute, l=length of travel of the drill in mm, n= rpm of the drill and s=feed per revolution of the drill in mm.
a) 5
b) 10
c) 20
d) none of the mentioned
View Answer

Answer: c
Explanation: From the formula, t= l / (n*s). Here t=2, n=2 and s=5. Put all these values with their units in the mentioned equation,you will easily get the answer as 20 mm.

11. If d=2, n=1 and f=2. Then find the value of m. d= diameter of drill in mm, n=rpm, f=feed per revolution in mm and m=metal removal rate in mm3/minute.
a) 3.14
b) 6.28
c) 12.56
d) none of the mentioned
View Answer

Answer: b
Explanation: From the formula, m= (3.14*d*d*n*f) / 4, we can easily get the value of m. Metal removal rate means the rate at which the metal is removed during the operation.

12. If d=2, n=2 and m=3. Then find the value of f. d= diameter of drill in mm, n=rpm, f=feed per revolution in mm and m=metal removal rate in mm3/minute.
a) 0.238
b) 0.477
c) 0.119
d) none of the mentioned
View Answer

Answer: b
Explanation: From the formula, m= (3.14*d*d*n*f) / 4, we can easily get the value of feed. Feed may also be expressed as feet per minute or mm/minute.

13. If m=5, n=2 and f=3. Then find the value of m. d= diameter of drill in mm, n=rpm, f=feed per revolution in mm and m=metal removal rate in mm3/minute.
a) 1.03
b) 1.065
c) 0.266
d) none of the mentioned
View Answer

Answer: b
Explanation: From the formula, m= (3.14*d*d*n*f) / 4, we can easily find the value of m.

14. If cs=0.942 and d=60, then find the value of n. d=diameter of drill in mm, n=rpm and cs=cutting speed in mm/minute.
a) 15.7
b) 15700
c) 5
d) 5000
View Answer

Answer: c
Explanation: From the formula, cs = (3.14*d*n) /1000, we can easily find value of n. N means rpm-revolution per minute. It is an important term in any operation.

Sanfoundry Global Education & Learning Series – Machine Tools and Machining.
To practice all areas of Machine Tools and Machining, here is complete set of 1000+ Multiple Choice Questions and Answers.

If you find a mistake in question / option / answer, kindly take a screenshot and email to [email protected]

advertisement
advertisement
Subscribe to our Newsletters (Subject-wise). Participate in the Sanfoundry Certification contest to get free Certificate of Merit. Join our social networks below and stay updated with latest contests, videos, internships and jobs!

Youtube | Telegram | LinkedIn | Instagram | Facebook | Twitter | Pinterest
Manish Bhojasia - Founder & CTO at Sanfoundry
Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He lives in Bangalore, and focuses on development of Linux Kernel, SAN Technologies, Advanced C, Data Structures & Alogrithms. Stay connected with him at LinkedIn.

Subscribe to his free Masterclasses at Youtube & discussions at Telegram SanfoundryClasses.