Machine Kinematics Questions and Answers – Simple Harmonic Motion

This set of Machine Kinematics Multiple Choice Questions & Answers (MCQs) focuses on “Simple Harmonic Motion”.

1. The periodic time (tp) is given by
a) ω / 2 π
b) 2 π / ω
c) 2 π × ω
d) π/ω
View Answer

Answer: b
Explanation: Periodic time is the time taken for one complete revolution of the particle.
∴ Periodic time, tp = 2 π/ω seconds.

2. The velocity of a particle moving with simple harmonic motion is . . . . at the mean position.
a) zero
b) minimum
c) maximum
d) none of the mentioned
View Answer

Answer: c
Explanation: At mean the value of x = 0. Therefore, it is maximum at mean position.
Vmax = ω.r.

3. The velocity of a particle (v) moving with simple harmonic motion, at any instant is given by
a) ω √r2 − x2
b) ω √x2 − r2
c) ω2 √r2 − x2
d) ω2√x2 − r2
View Answer

Answer: a
Explanation: Velocity of any particle vN = vsinθ = ω.rsinθ = ω √r2 − x2.

advertisement
advertisement

4. The maximum acceleration of a particle moving with simple harmonic motion is
a) ω
b) ω.r
c) ω2.r
d) ω2/r
View Answer

Answer: c
Explanation: Acceleration, aN = ω2.rcosθ = ω2.r.

5. The frequency of oscillation for the simple pendulum is
a) 1/2π √L/g
b) 1/2π √g/L
c) 2π √L/g
d) 2π√g/L
View Answer

Answer: b
Explanation: The motion of the bob from one extremity to the other is known as beat or swing. Thus one beat = 1/2 oscillation.
∴ Periodic time for one beat = π √g/L
∴ Frequency = 1/2π √g/L.
Sanfoundry Certification Contest of the Month is Live. 100+ Subjects. Participate Now!

6. When a rigid body is suspended vertically and it oscillates with a small amplitude under the action of the force of gravity, the body is known as
a) simple pendulum
b) torsional pendulum
c) compound pendulum
d) second’s pendulum
View Answer

Answer: c
Explanation: When a rigid body is suspended vertically, and it oscillates with a small amplitude under the action of the force of gravity, the body is known as compound pendulum. Thus the periodic time of a compound pendulum is minimum when the distance between the point of suspension and the centre of gravity is equal to the radius of gyration of the body about its centre of gravity.

7. The frequency of oscillation of a compound pendulum is
a) 1/2π √g.h/k2G +h2
b) 1/2π √k2G +h2/g.h
c) 2π√g.h/k2G +h2
d) 2π√k2G +h2/g.h
View Answer

Answer: a
Explanation: We know that the periodic time,
tp = 2π√Displacement/Accleration = 2π√θ/α
and frequency of oscillation,n = 1/tp = 1/2π √g.h/k2G +h2
where kG = Radius of gyration about the centroidal axis, and
h = Distance between the point of suspension and centre of gravity of the body.
advertisement

8. The equivalent length of a simple pendulum which gives the same frequency as the compound pendulum is
a) h/ k2G +h2
b) k2G +h2/h
c) h2/k2G +h2
d) k2G +h2/h2
View Answer

Answer: b
Explanation: By comparing the frequencies of simple pendulum to compound pendulum we get the equivalent length of simple pendulum as k2G +h2/h.

9. The centre of percussion is below the centre of gravity of the body and is at a distance equal to
a) h / kG
b) h.kG
c) h2/kG
d) k2G/h
View Answer

Answer: d
Explanation: The centre of oscillation is sometimes termed as centre of percussion. It is defined as that point at which a blow may be struck on a suspended body so that the reaction at the support is zero. The centre of percussion is below the centre of gravity and at a distance k2G/h. The distance between the centre of suspension and the centre of percussion is equal to the equivalent length of a simple pendulum.
advertisement

10. The frequency of oscillation of a torsional pendulum is
a) 2πkG/r √g/I
b) r/2πkG√g/I
c) 2πkG/r√I/g
d) r/2πkG√I/g
View Answer

Answer: b
Explanation: None.

Sanfoundry Global Education & Learning Series – Machine Kinematics.
To practice all areas of Machine Kinematics, here is complete set of 1000+ Multiple Choice Questions and Answers.

If you find a mistake in question / option / answer, kindly take a screenshot and email to [email protected]

advertisement
advertisement
Subscribe to our Newsletters (Subject-wise). Participate in the Sanfoundry Certification contest to get free Certificate of Merit. Join our social networks below and stay updated with latest contests, videos, internships and jobs!

Youtube | Telegram | LinkedIn | Instagram | Facebook | Twitter | Pinterest
Manish Bhojasia - Founder & CTO at Sanfoundry
Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He lives in Bangalore, and focuses on development of Linux Kernel, SAN Technologies, Advanced C, Data Structures & Alogrithms. Stay connected with him at LinkedIn.

Subscribe to his free Masterclasses at Youtube & discussions at Telegram SanfoundryClasses.