Machine Kinematics Questions and Answers – Friction in Journal Bearing- Friction Circle

This set of Machine Kinematics Multiple Choice Questions & Answers (MCQs) focuses on “Friction in Journal Bearing- Friction Circle”.

1. The minimum force required to slide a body of weight W on a rough horizontal plane is
a) W sinϴ
b) W cosϴ
c) W tanϴ
d) W cosecϴ
View Answer

Answer: a
Explanation: The minimum force required to slide a body of weight W on a rough horizontal plane is W sinϴ. A body of weight W is required to move up the rough inclined plane whose angle of inclination with the horizontal is α. The effort applied parallel to the plane is given by P = W (sinα + μ cosα).

2. A body will begin to move down an inclined plane, if the angle of inclination of the plane is ____________ the angle of friction.
a) equal to
b) less than
c) greater than
d) none of the mentioned
View Answer

Answer: c
Explanation: None.

3. A body of weight W is required to move up the rough inclined plane whose angle of inclination with the horizontal is α. The effort applied parallel to the plane is given by
a) P = W tanα
b) P = W tan (α + ɸ)
c) P = W (sinα + μ cosα)
d) P = W (cosα + μ sinα)
View Answer

Answer: c
Explanation: The minimum force required to slide a body of weight W on a rough horizontal plane is W sinϴ. A body of weight W is required to move up the rough inclined plane whose angle of inclination with the horizontal is α. The effort applied parallel to the plane is given by P = W (sinα + μ cosα).
advertisement
advertisement

4. The coefficient of friction is the ratio of the limiting friction to the normal reaction between the two bodies.
a) True
b) False
View Answer

Answer: a
Explanation: The coefficient of friction is defined as the ratio of the limiting friction(F) to the normal reaction(RN) between the two bodies. Mathematically,
μ = F/RN.

5. In a screw jack, the effort required to lift the load W is given by
a) P = W tan (α – ɸ)
b) P = W tan (α + ɸ)
c) P = W tan (ɸ – α)
d) P = W cos (α + ɸ)
View Answer

Answer: b
Explanation: The effort required at the circumference of the screw to lift the load W is given by
P = W tan (α + ɸ)
The effort required at the circumference of the screw to lower the load W is given by
P = W tan (ɸ – α).
Sanfoundry Certification Contest of the Month is Live. 100+ Subjects. Participate Now!

6. In a screw jack, the effort required to lower the load W is given by
a) P = W tan (α – ɸ)
b) P = W tan (α + ɸ)
c) P = W tan (ɸ – α)
d) P = W cos (α + ɸ)
View Answer

Answer: c
Explanation: The effort required at the circumference of the screw to lower the load W is given by
P = W tan (ɸ – α)
The effort required at the circumference of the screw to lift the load W is given by
P = W tan (α + ɸ).

7. The frictional torque for square thread at the mean radius r while raising load W is given by
a) T = W.rtan(α – ɸ)
b) T = W.rtan(α + ɸ)
c) T = W.rtanα
d) T = W.rtanɸ
View Answer

Answer: b
Explanation: None.
advertisement

8. Efficiency of a screw jack is given by
a) tan(α + ɸ)/tanα
b) tanα/ tan(α + ɸ)
c) tan(α – ɸ)/tanα
d) tanα/tan(α – ɸ)
View Answer

Answer: b
Explanation: None.

9. The load cup of a screw jack is made separate from the head of the spindle to
a) enhance the load carrying capacity of the jack
b) reduce the effort needed for lifting the working load
c) reduce the value of frictional torque required to be countered for lifting the load
d) prevent the rotation of load being lifted
View Answer

Answer: d
Explanation: In screw jack, the load to be raised or lowered, is placed on the head of the square threaded rod which is rotated by the application of an effort at the end of the lever for lifting or lowering the load.
advertisement

10. The efficiency of the a screw jack is maximum, when
a) α = 450 + ɸ/2
b) α = 450 – ɸ/2
c) α = 900 + ɸ
d) α = 900 – ɸ
View Answer

Answer: b
Explanation: None.

Sanfoundry Global Education & Learning Series – Machine Kinematics.
To practice all areas of Machine Kinematics, here is complete set of 1000+ Multiple Choice Questions and Answers.

If you find a mistake in question / option / answer, kindly take a screenshot and email to [email protected]

advertisement
advertisement
Subscribe to our Newsletters (Subject-wise). Participate in the Sanfoundry Certification contest to get free Certificate of Merit. Join our social networks below and stay updated with latest contests, videos, internships and jobs!

Youtube | Telegram | LinkedIn | Instagram | Facebook | Twitter | Pinterest
Manish Bhojasia - Founder & CTO at Sanfoundry
Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He lives in Bangalore, and focuses on development of Linux Kernel, SAN Technologies, Advanced C, Data Structures & Alogrithms. Stay connected with him at LinkedIn.

Subscribe to his free Masterclasses at Youtube & discussions at Telegram SanfoundryClasses.