Machine Design Questions and Answers – Shaft Design

This set of Machine Design Multiple Choice Questions & Answers (MCQs) focuses on “Shaft Design”.

1. While designing shaft on the basis of torsional rigidity, angle of twist is given by?
a) Ml/Gd⁴
b) 584Ml/Gd⁴
c) 292 Ml/Gd⁴
d) None of the mentioned
View Answer

Answer: b
Explanation: θ=(180/π)xMl/GJ where J=πd⁴/32.

2. According to the ASME code, maximum allowable shear stress is taken as X% of yield strength or Y% of ultimate strength.
a) X=30 Y=18
b) X=30 Y=30
c) X=18 Y=18
d) X=18 Y=30
View Answer

Answer: a
Explanation: ASME Standard. The lesser value is taken among the two.

3. Does ASME Standard take into consideration shock and fatigue factors?
a) Yes
b) No
View Answer

Answer: a
Explanation: Moment is multiplied by a number to consider these factors while designing the shaft.
advertisement
advertisement

4. The layout of a shaft supported on bearings at A & B is shown. Power is supplied by means of a vertical belt on pulley B which is then transmitted to pulley C carrying a horizontal belt. The angle of wrap is 180’ and coefficient of friction is 0.3. Maximum permissible tension in the rope is 3kN. The radius of pulley at B & C is 300mm and 150mm. Calculate the torque supplied to the shaft.
Find the torque supplied to the shaft for radius of pulley at B & C is 300mm & 150mm
a) 453.5N-m
b) 549.3N-m
c) 657.3N-m
d) None of the listed
View Answer

Answer: b
Explanation: M=(P₁-P₂)xR where P₁=3000N, P₂=P₁/e^(Coeff of friction x Angle of wrap).

5. The layout of a shaft supported on bearings at A & B is shown. Power is supplied by means of a vertical belt on pulley B which is then transmitted to pulley C carrying a horizontal belt. The angle of wrap is 180’ and coefficient of friction is 0.3. Maximum permissible tension in the rope is 3kN. The radius of pulley at B & C is 300mm and 150mm. Calculate the tension in the rope of pulley C.
Find the torque supplied to the shaft for radius of pulley at B & C is 300mm & 150mm
a) 6778.3N and 7765.3N
b) 5948.15N and 2288.75N
c) 5468.4N ad 8678.3N
d) None of the listed
View Answer

Answer: b
Explanation: (P₃-P₄)x150=549.3×1000 and P₃/P₄=2.6. Hence P₃=5948.15N and P₄=2288.75N.

6. The layout of a shaft supported on bearings at A & B is shown. Power is supplied by means of a vertical belt on pulley B which is then transmitted to pulley C carrying a horizontal belt. The angle of wrap is 180’ and coefficient of friction is 0.3. Maximum permissible tension in the rope is 3kN. The radius of pulley at B & C is 300mm and 150mm. If allowable shear stress in the shaft is 70N/mm² and torsional and bending moments are M=1185000N-mm and m=330000N-mm, find the diameter of the shaft.
Find the torque supplied to the shaft for radius of pulley at B & C is 300mm & 150mm
a) 36.8mm
b) 39.7mm
c) 44.7mm
d) 40.3mm
View Answer

Answer: c
Explanation: 70=(16/πdᵌ)x√M²+m².

7. The layout of a shaft supported on bearings at A & B is shown. Power is supplied by means of a vertical belt on pulley B which is then transmitted to pulley C carrying a horizontal belt. The angle of wrap is 180’ and coefficient of friction is 0.3. Maximum permissible tension in the rope is 3kN. The radius of pulley at B & C is 300mm and 150mm. If bending moment on point B in horizontal plate is M and in vertical plane is m, then the net bending moment at point B is?
Find the torque supplied to the shaft for radius of pulley at B & C is 300mm & 150mm
a) M
b) m
c) M+m
d) √M²+m²
View Answer

Answer: d
Explanation: The two moments act perpendicularly to each other.
advertisement

8. Calculate the shaft diameter on rigidity basis if torsional moment is 196000N-mm, length of shaft is 1000mm. Permissible angle of twist per meter is 0.5’ and take G=79300N/mm².
a) None of the listed
b) 41.2mm
c) 35.8mm
d) 38.8mm
View Answer

Answer: b
Explanation: d⁴=584Ml/Gθ.

9. If yielding strength=400N/mm², the find the permissible shear stress according to ASME standards.
a) 72 N/mm²
b) 76 N/mm²
c) 268 N/mm²
d) 422 N/mm²
View Answer

Answer: a
Explanation: 0.18×400.
advertisement

10. The stiffness of solid shaft is more than the stiffness of hollow shaft with same weight.
a) True
b) False
View Answer

Answer: b
Explanation: Hollow shaft is more stiff.

11. The strength of hollow shaft is more than the strength of solid shaft of same weight.
a) True
b) False
View Answer

Answer: a
Explanation: Outer fibers are more effective in resisting the applied moments. In hollow shafts material is removed and spread on a larger radius.

12. Solid shaft is costlier than hollow shaft of same weight.
a) True
b) False
View Answer

Answer: b
Explanation: Hollow shaft cost is more as material is to be selectively emplaced.

13. Solid shafts are used in epicyclic gearboxes.
a) True
b) False
View Answer

Answer: b
Explanation: In epicyclic gears, one shaft rotates inside other and hence hollow shafts are used.

14. Flexible shafts have _______ rigidity in torsion making them flexible.
a) Low
b) High
c) Very high
d) Infinitely small
View Answer

Answer: b
Explanation: Flexible shafts have high rigidity in torsion making then capable to transmit torque.

15. Flexible shafts have ______ rigidity in bending moment.
a) High
b) Low
c) Very high
d) Extremely low
View Answer

Answer: b
Explanation: Flexible shafts have low rigidity in bending moments making them flexible.

Sanfoundry Global Education & Learning Series – Machine Design.
To practice all areas of Machine Design, here is complete set of 1000+ Multiple Choice Questions and Answers.

advertisement
advertisement
Subscribe to our Newsletters (Subject-wise). Participate in the Sanfoundry Certification contest to get free Certificate of Merit. Join our social networks below and stay updated with latest contests, videos, internships and jobs!

Youtube | Telegram | LinkedIn | Instagram | Facebook | Twitter | Pinterest
Manish Bhojasia - Founder & CTO at Sanfoundry
Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He lives in Bangalore, and focuses on development of Linux Kernel, SAN Technologies, Advanced C, Data Structures & Alogrithms. Stay connected with him at LinkedIn.

Subscribe to his free Masterclasses at Youtube & discussions at Telegram SanfoundryClasses.