This set of Machine Design Multiple Choice Questions & Answers (MCQs) focuses on “Eccentrically Loaded Riveted Joints”.
Explanation: Primary Shear act vertically upward on all the rivets. Secondary shear is proportional to the distance from CG. Hence rivets 1 and 4 are under maximum stress.
Explanation: τ₁=P/4A or 7500/A.
3. If secondary shear stress acting on any bolts is given by Cxr₁ where r₁ is the distance of bolt from CG, then find the value of C. Bolts are equidistant with spacing of 100mm. Force P=30kN.
4. Calculate the effective force in vector form to which rivet 2 is subjected. Bolts are separated by 100mm and force P=30kN.
d) None of the listed
Explanation: Primary force=7500j, Sec Force=Cx50(-i) where C=72.
5. Calculate the effective force in vector form to which rivet 4 is subjected. Bolts are separated by 100mm and force P=30kN.
b) None of the listed
Explanation: Primary force=7500j, Sec Force=Cx100 i where C=72.
Explanation: Magnitude of force acting on Bolt 4 or Bolt 1=√7500²+7200² or 10396.6=πd²τ/4.
Explanation: Primary shear force is same but secondary shear forces direction are different in the two bolts.
Explanation: Although the vectors are different for the forces on two bolts but their magnitudes are same.
9. Can we use the rivets of diameter 18mm in the following case if P=30kN and bolts are separated by 100mm each. Maximum permissible shear stress is 60N/mm².
c) In some cases
d) Cannot be determined
Explanation: The minimum diameter required for the rivets is obtained 15mm. Any rivet greater than this diameter is safe to use.
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