Java Program to Print Odd Elements at Odd Index

This is the Java Program to Print Odd Elements at Odd Index Number.

Problem Description

Given an array of integers, print the odd numbers present at odd index numbers.
Example:

Array = [2,1,4,4,5,7]

Output = 1,7

Problem Solution

Iterate through the array, and check whether the current index is even or odd. If it is odd then check the element at that index to be even or odd, print the element if it is odd.

Program/Source Code

Here is the source code of the Java Program to Print Odd Elements at Odd Index Number. The program is successfully compiled and tested using IDE IntelliJ Idea in Windows 7. The program output is also shown below.

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//Java Program to Print Odd Elements at Odd Index Number

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import java.io.BufferedReader;
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import java.io.InputStreamReader;
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public class OddIndexedOddElements {
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    // Function to print Odd Elements present at Odd Index Number

    static void printOddIndexedElements(int[] array){

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        int i=0;
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        for(i=0; i<array.length; i++){
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            if(i%2 != 0 && array[i]%2 !=0){

                System.out.print(array[i] + " ");

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            }
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        }
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    }
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    // Function to read user input
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    public static void main(String[] args) {

        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

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        int size;
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        System.out.println("Enter the size of the array");

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        try {
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            size = Integer.parseInt(br.readLine());

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        } catch (Exception e) {
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            System.out.println("Invalid Input");

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            return;
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        }
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        int[] array = new int[size];
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        System.out.println("Enter array elements");

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        int i;
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        for (i = 0; i < array.length; i++) {

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            try {
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                array[i] = Integer.parseInt(br.readLine());

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            } catch (Exception e) {
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                System.out.println("An error occurred");

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                return;
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            }
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        }
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        System.out.println("Output");
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        printOddIndexedElements(array);
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    }
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}
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Program Explanation

1. In function printOddIndexedElements(), the loop for(i=0; i<array.length; i++) iterates through the array.
2. Then using the condition if(i%2 != 0 && array[i]%2 != 0), we first check whether the current index is odd.
3. If the index is odd, then we check the element at that index (the condition after the && operator), if the element is odd, then display the element.

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Time Complexity: O(n) where n is the number of elements in the array.

Runtime Test Cases

 
Case 1 (Positive test Case - having odd elements at odd index):
 
Enter the size of the array
6
Enter array elements
2
1
4
4
5
7
Output
1 7 
 
Case 2 (Negative test Case - no odd element present at odd index):
 
Enter the size of the array
5
Enter array elements
1
2
3
4
5
Output

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