Java Program to Generate All Subsets of a Given Set in the Lexico Graphic Order

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This is a java program to generate and print all the subsets of a given set as per lexicographical order, here we follow the numerical sequence. First generate all the subsets having only one element, then generate all the subsets having two elements and so on.

Here is the source code of the Java Program to Generate All Subsets of a Given Set in the Lexico-Graphic Order. The Java program is successfully compiled and run on a Windows system. The program output is also shown below.

  1. //This is a java program to generate all permutation of n elements in lexicographic order
  2. import java.util.Random;
  3. import java.util.Scanner;
  4.  
  5. public class Lexicographic_Permutation 
  6. {
  7.     public static int[] lexicographicOrder(int N) 
  8.     {
  9.         int[] binary = new int[(int) Math.pow(2, N)];
  10.         for (int i = 0; i < Math.pow(2, N); i++) 
  11.         {
  12.             int b = 1;
  13.             binary[i] = 0;
  14.             int num = i;
  15.             while (num > 0) 
  16.             {
  17.                 binary[i] += (num % 2) * b;
  18.                 num /= 2;
  19.                 b = b * 10;
  20.             }
  21.         }
  22.         return binary;
  23.     }
  24.  
  25.     public static void main(String args[]) 
  26.     {
  27.         Random random = new Random();
  28.         Scanner sc = new Scanner(System.in);
  29.         System.out.println("Enter the number of elements in the set: ");
  30.         int N = sc.nextInt();
  31.         int[] sequence = new int[N];
  32.         for (int i = 0; i < N; i++)
  33.             sequence[i] = Math.abs(random.nextInt(100));
  34.  
  35.         System.out.println("The elements in the set : ");
  36.         for (int i = 0; i < N; i++)
  37.             System.out.print(sequence[i] + " ");
  38.  
  39.         for (int i = 1; i < N; i++) 
  40.         {
  41.             int j = i;
  42.             int temp = sequence[i];
  43.             while (j > 0 && temp < sequence[j - 1]) 
  44.             {
  45.                 sequence[j] = sequence[j - 1];
  46.                 j = j - 1;
  47.             }
  48.             sequence[j] = temp;
  49.         }
  50.  
  51.         int[] mask = new int[(int) Math.pow(2, N)];
  52.         mask = lexicographicOrder(N);
  53.  
  54.         System.out.println("\nThe permutations are: ");
  55.         for (int i = 0; i < Math.pow(2, N); i++) 
  56.         {
  57.             System.out.print("{ ");
  58.             for (int j = 0; j < N; j++) 
  59.             {
  60.                 if (mask[i] % 10 == 1)
  61.                     System.out.print(sequence[j] + " ");
  62.                 mask[i] /= 10;
  63.             }
  64.             System.out.println("}");
  65.         }
  66.         sc.close();
  67.     }
  68. }

Output:

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$ javac Lexicographic_Permutation.java
$ java Lexicographic_Permutation
 
Enter the number of elements in the set: 
5
The elements in the set : 
19 3 37 7 22 
The permutations are: 
{ }
{ 3 }
{ 7 }
{ 19 }
{ 22 }
{ 37 }
{ 3 7 }
{ 3 19 }
{ 7 19 }
{ 3 22 }
{ 7 22 }
{ 19 22 }
{ 3 37 }
{ 7 37 }
{ 19 37 }
{ 22 37 }
{ 3 7 19 }
{ 3 7 22 }
{ 3 19 22 }
{ 7 19 22 }
{ 3 7 37 }
{ 3 19 37 }
{ 7 19 37 }
{ 3 22 37 }
{ 7 22 37 }
{ 19 22 37 }
{ 3 7 22 37 }
{ 3 19 22 37 }
{ 7 19 22 37 }
{ 3 7 19 37 }
{ 3 7 19 22 }
{ 3 7 19 22 37 }

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Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He is Linux Kernel Developer & SAN Architect and is passionate about competency developments in these areas. He lives in Bangalore and delivers focused training sessions to IT professionals in Linux Kernel, Linux Debugging, Linux Device Drivers, Linux Networking, Linux Storage, Advanced C Programming, SAN Storage Technologies, SCSI Internals & Storage Protocols such as iSCSI & Fiber Channel. Stay connected with him @ LinkedIn | Youtube | Instagram | Facebook | Twitter