Java Program to Find the Sum of n Square Numbers

This is the Java Program to Find the Sum of n Square Numbers.

Problem Description

Given an integer says n, find out the sum of the first n squared numbers.

Problem Solution

The sum of the first n squared numbers can be calculated using the formula :

sum = n*(n+1)*(2n+1)/6

Program/Source Code

Here is the source code of the Java Program to Find the Sum of n Square Numbers. The program is successfully compiled and tested using IDE IntelliJ Idea in Windows 7. The program output is also shown below.

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//Java Program to Find the Sum of n Square Numbers

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import java.io.BufferedReader;
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import java.io.InputStreamReader;
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public class SumOfNSquareNumbers {
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    // Function to read n and display the sum

    public static void main(String[] args) {

        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

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        int n;
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        System.out.println("Enter the value of n");

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        try{
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            n = Integer.parseInt(br.readLine());

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        }catch (Exception e){
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            System.out.println("An error occurred");

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            return;
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        }
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        if(n<0){
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            System.out.println("n cannot take negative values");

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            return;
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        }
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        double sum = n*(n+1)*(2*n+1)/6;
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        System.out.println("The sum of first " + n + " squared numbers is " + sum);

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    }
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}
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Program Explanation

In the function main(), firstly an integer n is entered and then the sum is calculated as per the line,
double sum = n*(n+1)*(2*n+1)/6. Finally, the sum is displayed.

Time Complexity: O(1).

Runtime Test Cases

 
Case 1 (Simple Test Case):
 
Enter the value of n
15
The sum of first 15 squared numbers is 1240.0

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