This is the Java Program to Find the Sum of n Cube Numbers.
Problem Description
Given an integer says n, find out the sum of the first n cubed numbers.
Problem Solution
The sum of the first n cubed numbers can be calculated using the formula :
sum = (n*(n+1)/2)2
Program/Source Code
Here is the source code of the Java Program to Find the Sum of n Cube Numbers. The program is successfully compiled and tested using IDE IntelliJ Idea in Windows 7. The program output is also shown below.
//Java Program to Find the Sum of n Cube Numbers
import java.io.BufferedReader;
import java.io.InputStreamReader;
public class SumOfNCubeNumbers {
// Function to read n and display the sum
public static void main(String[] args) {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int n;
System.out.println("Enter the value of n");
try{
n = Integer.parseInt(br.readLine());
}catch (Exception e){
System.out.println("An error occurred");
return;
}
if(n<0){
System.out.println("n cannot take negative values");
return;
}
double sum = Math.pow(n*(n+1)/2,2);
System.out.println("The sum of first " + n + " cube numbers is " + sum);
}
}
Program Explanation
In the function main(), firstly an integer n is entered and then the sum is calculated as per the line,
double sum = Math.pow(n*(n+1)/2,2). Finally, the sum is displayed.
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Time Complexity: O(1).
Runtime Test Cases
Case 1 (Simple Test Case): Enter the value of n 15 The sum of first 15 cube numbers is 14400.0
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