Java Program to Find Peak Element of an Array using Naive Method

This is a Java Program to find peak element of an array. A peak element of an array is that element which is not smaller than its neighbors. Consider only one neighbour for corner elements. The time complexity of the following program is O (n).

Brute Force Algorithm is as follows :

for i in range (n) :
    if A[i - 1] <= A[i] >= A[i + 1] :
        print A[i]
    end if
end for

Here is the source code of the Java program to find peak element of an array. The Java program is successfully compiled and run on a Windows system. The program output is also shown below.

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/*
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 *    Java Program to Find the peak element of an array O(n) time (Naive Method)

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 */
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import java.util.Scanner;
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public class PeakElement1
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{
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    public static void main(String[] args)

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    {    
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        Scanner scan = new Scanner(System.in);

        System.out.println("Enter size of array");

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        int N = scan.nextInt();
```
```
        int[] arr = new int[N + 2];
```

        /* set corner values to -infinity */

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        arr[0] = Integer.MIN_VALUE;
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```
        arr[N + 1] = Integer.MIN_VALUE;
```
```
 
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        /* Accept N elements */
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        System.out.println("Enter "+ N +" elements");

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        for (int i = 1; i <= N; i++)
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```
            arr[i] = scan.nextInt();
```
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        /* Find All Peak Elements */
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        System.out.println("\nAll Peak Elements : ");

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        for (int i = 1; i <= N; i++)
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            if (arr[i - 1] <= arr[i] && arr[i] >= arr[i + 1])

                System.out.println(arr[i] +" at position "+ i);

```
 
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        System.out.println();    
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    }         
```
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}
```

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Enter size of array
6
Enter 6 elements
1 2 5 5 4 1
 
All Peak Elements :
5 at position 3
5 at position 4
 
 
 
Enter size of array
7
Enter 7 elements
6 24 15 2 23 99 67
 
All Peak Elements :
24 at position 2
99 at position 6
 
 
 
Enter size of array
10
Enter 10 elements
10 9 8 24 8 7 97 28 17 63
 
All Peak Elements :
10 at position 1
24 at position 4
97 at position 7
63 at position 10