This set of Highway Engineering Questions and Answers for Campus interviews focuses on “Structural Evaluation of Flexible Pavements and Strengthening by Overlay – 3”.
1. The deflection value D is obtained from multiplying the difference of initial and final gauge difference of ___________
Explanation: The deflection value D is given by D=2(Do-Df).
2. The difference between initial and final deflection should not exceed ____ mm, for no leg correction value.
Explanation: The difference between the initial and final deflection should not exceed 0.025m or 2.5 division.
3. The statistical analysis of data doesn’t require ___________
a) Mean deflection
b) Standard deviation
c) Characteristics deflection
Explanation: The statistical analysis of data requires mean deflection, characteristics deflection and standard deviation.
4. The characteristics deflection value is ___________
Explanation: The characteristics deflection is given by Dm+s, where Dm is the mean deflection and s is the standard deviation.
5. The sum of 15 deflections is 100, find the mean deflection.
Explanation: The deflection is given by 100/15=6.66, where 100 is the mean deflection and 15 is the number of observations.
6. The deflection correction will be negative if the temperature exceeds ___________
Explanation: In India the temperature is considered as 35°c for evaluation of pavement because India is a sub tropical and hot country.
7. The Overlay thickness depends on how many factors?
Explanation: The overlay thickness depends on two major factors namely stability and CASA.
8. The VDF is assumed as 4.5 for commercial vehicle count of ___________
Explanation: The vehicle damage factor is assumed as 4.5, for commercial vehicle count of more than 1500.
9. The thickness of the flexible overlay is given by ___________
Explanation: The thickness of flexible overlay is given by hd-he, where hd is the thickness of the new design pavement and he is the existing pavement height.
10. The spacing between longitudinal joints may be ___________
a) 3.0 m
b) 3.2 m
c) 3.5 m
d) 4.0 m
Explanation: IRC recommends a value of 3.5 m for pavement, So the spacing is equal to the width of pavement.
Sanfoundry Global Education & Learning Series – Highway Engineering.
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