This set of Fluid Mechanics Multiple Choice Questions & Answers (MCQs) focuses on “Gradually Varied Flow(GVF) – 2”.

1. If the value of rate of change of specific energy is 7.79×10^{-4} m and S_{f} = 0.00013, calculate the value of bed slope.

a) 1 in 1000

b) 1 in 1100

c) 1 in 1200

d) 1 in 1300

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Explanation:

^{dE}⁄

_{dx}= S

_{0}– S

_{f}; S

_{0}= 1 in 1100.

2. Calculate the rate of change of depth of a rectangular channel having depth 1m and width 4m. Given: C = 40, S_{0} = 1/900, S_{f} = 0.0005

a) 4.94×10^{-4} m

b) 5.94×10^{-4} m

c) 6.94×10^{-4} m

d) 7.94×10^{-4} m

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3. Calculate the rate of change of depth of a triangular channel if the depth is 4m and the side slope is1H:2V. Given:S_{0} = 1 in 1500;S_{f} = 0.00004 and n=0.010.

a) 8.95×10^{-4}m

b) 9.95×10^{-4}m

c) 10.95×10^{-4}m

d) 11.95×10^{-4} m

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4. Calculate the value of S_{f} for a trapezoidal channel having depth 2m, width 5m and side slope of 1H:1.5V. Given: dy/dx=1.18×10^{-3},S_{0} = 1 in 1000, C = 50.

a) 0.00001

b) 0.00002

c) 0.00003

d) 0.00004

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5. Determine the rate of change of depth of a rectangular channel having dimensions 2m×3m and the velocity of flow is 2 m/s.

Given:S_{0} = 1 in 500 and S_{f} = 0.0007.

a) 0.63m

b) 1.63m

c) 2.63m

d) 3.63m

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6. Calculate the velocity of flow in a triangular channel having depth 7m and the side slope of the channel is 1H:4V if the bed slope of the channel is 1 in 1200 and the slope of the energy line is 0.00010. Given:( dy)/dx=7.55m.

a) 1 m/s

b) 2 m/s

c) 3 m/s

d) 4 m/s

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7. Calculate the value of bed slope of a trapezoidal channel having depth 2m and width 2.5m with a side slope of1H:3V. Given: dy/dx=1.43×10^{-3}; S_{f} = 0.00002; V = 1.5 m/s.

a) 1 in 1000

b) 1 in 900

c) 1 in 800

d) 1 in 700

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8. The dimensions of a rectangular channel section is2.5m×1m. Calculate the value of S_{f} if the bed slope of the channel is 1 in 600. Given: dy/dx=1.52×10^{-3}m.

a) 0.0002

b) 0.0003

c) 0.0004

d) 0.0005

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9. The dimensions of a rectangular channel section is 2.5m×1m. Calculate the rate of change of specific energy if the rate of change of depth is 1.52×10^{-3}m.

a) 1.17×10^{-3}m

b) 2.00×10^{-3}m

c) 2.03×10^{-3}m

d) 2.06×10^{-3}m

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10. Calculate the value of rate of change of specific energy for a triangular channel having depth 3.5m and the side slope is 1H:2V. Given:V = 2.5 m/s, dy/dx=8.6×10^{-4}.

a) 3.47×10^{-4}m

b) 4.47×10^{-4}m

c) 5.47×10^{-4}m

d) 6.47×10^{-4}m

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**Sanfoundry Global Education & Learning Series – Fluid Mechanics.**

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