Fluid Mechanics Questions and Answers – Gradually Varied Flow(GVF) – 2

This set of Fluid Mechanics Multiple Choice Questions & Answers (MCQs) focuses on “Gradually Varied Flow(GVF) – 2”.

1. If the value of rate of change of specific energy is 7.79×10^-4 m and S_f = 0.00013, calculate the value of bed slope.
a) 1 in 1000
b) 1 in 1100
c) 1 in 1200
d) 1 in 1300
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2. Calculate the rate of change of depth of a rectangular channel having depth 1m and width 4m. Given: C = 40, S₀ = 1/900, S_f = 0.0005
a) 4.94×10^-4 m
b) 5.94×10^-4 m
c) 6.94×10^-4 m
d) 7.94×10^-4 m
View Answer

Answer: c
Explanation:

3. Calculate the rate of change of depth of a triangular channel if the depth is 4m and the side slope is1H:2V. Given:S₀ = 1 in 1500;S_f = 0.00004 and n=0.010.
a) 8.95×10^-4m
b) 9.95×10^-4m
c) 10.95×10^-4m
d) 11.95×10^-4 m
View Answer

Answer: a
Explanation:

4. Calculate the value of S_f for a trapezoidal channel having depth 2m, width 5m and side slope of 1H:1.5V. Given: dy/dx=1.18×10^-3,S₀ = 1 in 1000, C = 50.
a) 0.00001
b) 0.00002
c) 0.00003
d) 0.00004
View Answer

Answer: a
Explanation:

5. Determine the rate of change of depth of a rectangular channel having dimensions 2m×3m and the velocity of flow is 2 m/s.
Given:S₀ = 1 in 500 and S_f = 0.0007.
a) 0.63m
b) 1.63m
c) 2.63m
d) 3.63m
View Answer

Answer: b
Explanation:

6. Calculate the velocity of flow in a triangular channel having depth 7m and the side slope of the channel is 1H:4V if the bed slope of the channel is 1 in 1200 and the slope of the energy line is 0.00010. Given:( dy)/dx=7.55m.
a) 1 m/s
b) 2 m/s
c) 3 m/s
d) 4 m/s
View Answer

Answer: a
Explanation:

7. Calculate the value of bed slope of a trapezoidal channel having depth 2m and width 2.5m with a side slope of1H:3V. Given: dy/dx=1.43×10^-3; S_f = 0.00002; V = 1.5 m/s.
a) 1 in 1000
b) 1 in 900
c) 1 in 800
d) 1 in 700
View Answer

Answer: c
Explanation:

8. The dimensions of a rectangular channel section is2.5m×1m. Calculate the value of S_f if the bed slope of the channel is 1 in 600. Given: dy/dx=1.52×10^-3m.
a) 0.0002
b) 0.0003
c) 0.0004
d) 0.0005
View Answer

Answer: d
Explanation:

9. The dimensions of a rectangular channel section is 2.5m×1m. Calculate the rate of change of specific energy if the rate of change of depth is 1.52×10^-3m.
a) 1.17×10^-3m
b) 2.00×10^-3m
c) 2.03×10^-3m
d) 2.06×10^-3m
View Answer

Answer: a
Explanation:

10. Calculate the value of rate of change of specific energy for a triangular channel having depth 3.5m and the side slope is 1H:2V. Given:V = 2.5 m/s, dy/dx=8.6×10^-4.
a) 3.47×10^-4m
b) 4.47×10^-4m
c) 5.47×10^-4m
d) 6.47×10^-4m
View Answer

Answer: c
Explanation:

Sanfoundry Global Education & Learning Series – Fluid Mechanics.

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