This set of Fluid Mechanics Multiple Choice Questions & Answers (MCQs) focuses on “Gradually Varied Flow(GVF) – 1”.

1. Which of the following assumptions about a GVF is false?

a) Channel is prismatic

b) Pressure distribution is hydrostatic

c) Flow characteristics change with time

d) Roughness co efficient is constant

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Explanation: In a GVF, the flow is steady and hence the flow characteristics does not change with time.

2. Calculate the total discharge though a rectangular channel having depth 2m and width 4m if the value of C = 50 and if the slope of the energy line is 0.00004.

a) 1.53 m^{3}/s

b) 2.53 m^{3}/s

c) 3.53 m^{3}/s

d) 4.53 m^{3}/s

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3. Calculate S_{f} for a triangular channel if the depth of the channel is 5m and the side slope is 1H:2V. Given: Q = 5.80 m^{3}/s , C = 40.

a) 0.00010

b) 0.00011

c) 0.00012

d) 0.00013

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4. Calculate the discharge through a trapezoidal channel section if the depth of the channel is 3m and the base width is 3m. Given: C = 30, S_{f} = 0.0005, A = 12m^{2}.

a) 6.10 m^{3}/s

b) 7.10 m^{3}/s

c) 8.10 m^{3}/s

d) 9.10 m^{3}/s

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5. The discharge through a circular channel section having diameter 4m which is running half is 4.35 m^{3}/s and the value of slope of energy line is S_{f} = 0.0003, calculate the value of C.

a) 50

b) 45

c) 40

d) 35

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6. Determine the dynamic equation for the rate of change of depth having bed slope S_{0} and slope of total energy line S_{f}.

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7. Determine the dynamic equation for the rate of change of depth having bed slope S_{0} and slope of total energy line S_{f} in terms of Froude’s number.

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8. Estimate the rate of change of specific energy having bed slope S_{0} and slope of total energy line S_{f}.

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9. Calculate the rate of change of specific energy if the bed slope is 1 in 1000 and S_{f} = 0.00007.

a) 6.3×10^{-3}m

b) 7.3×10

c) 8.3×10^{-3}m

d) 9.3×10^{-3}m

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10. Estimate the value of S_{f} if the value of bed slope is 1 in 800 and and ^{dE}⁄_{dx} = 10^{-3}m.

a) 0.00015

b) 0.00025

c) 0.00035

d) 0.00045

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Explanation:

^{dE}⁄

_{dx}= S

_{0}– S

_{f}; S

_{f}= 0.00025.

**Sanfoundry Global Education & Learning Series – Fluid Mechanics.**

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