This set of Engineering Mechanics Multiple Choice Questions & Answers (MCQs) focuses on “Reduction of a Simple Distributed Loading”.

1. The uniformly distributed load is having two different values of load per unit length on the ends of the distribution.

a) True

b) False

View Answer

Explanation: The answer is no. The uniform distributed load is not having two different values of the load per unit meter on the corner. Rather the distribution is uniform. That is it is having the same value of the same on both of the corners.

2. There are two types of loading. The uniformly distributed and the non-uniformly distributed that is the one having two different values at corners.

a) The first part of the statement is false and other part is true

b) The first part of the statement is false and other part is false too

c) The first part of the statement is true and other part is false

d) The first part of the statement is true and other part is true too

View Answer

Explanation: The two forms of the loading are the uniformly distributed and the non-uniformly distributed that is the one having two different values at corners. The uniform distributed load is not having two different values of the load per unit meter on the corner.

3. The type of reduction of the loading is different for the uniformly distributed and the non-uniformly.

a) True

b) False

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Explanation: The methods for the reduction of the loadings are different for both uniformly distributed and the non-uniformly. In the latter, the simplification uses the quadratic equation. The latter also uses the integration for the same purpose.

4. Determine the magnitude of the resultant force acting on the shaft shown from left.

a) 640N

b) 675N

c) 620N

d) 610N

View Answer

Explanation: The net force will act at the centroid of the parabola. Whether it be a parabola or the cubic curve the centroid is the only point at which the net force act. Force can’t be acted horizontally if the loading is vertical. Hence whatever be the shape of the loading, the centroid is the point of action of net force.

5. In the simplification of the loading system, the net force acts at the ___________ of the loading body.

a) Centroid

b) The centre axis

c) The corner

d) The base

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Explanation: In the simplification of the loading system the net force acts at the centroid of the loading body. That is if the loading system is in the form of the triangle then the at the distance 2 by 3 of the base the net force of the loading will act. And the load will be half the area of the loading.

6. In triangle distributed loading, the loading at any distance can be easily found by using which of the following trigonometry function?

a) Tangent

b) Sine

c) Cosine

d) Sine inverse

View Answer

Explanation: In triangle distributed loading, the loading at any distance can be easily found by using Tangent trigonometry function. That is because the linear distance only determines the vertical loading. That is the loading is uniform along the linear distance. Is the linear distance is more the loading is more.

7. Determine the magnitude of the resultant force acting on the shaft shown. The length is 2m.

a) 160N

b) 16N

c) 169N

d) 111N

View Answer

Explanation: The net force will act at the centroid of the parabola. Whether it be a parabola or the cubic curve the centroid is the only point at which the net force act. Force can’t be acted horizontally if the loading is vertical. Hence whatever be the shape of the loading, the centroid is the point of action of net force.

8. If the non-Uniform loading is of the type of parabola then?

a) The net load will not be formed as all the forces will be cancelled

b) The net force will act the centre of the parabola

c) The net force will act on the base of the loading horizontally

d) The net force will act at the centroid of the parabola

View Answer

Explanation: The net force will act at the centroid of the parabola. Whether it be a parabola or the cubic curve the centroid is the only point at which the net force act. Force can’t be acted horizontally if the loading is vertical. Hence whatever be the shape of the loading, the centroid is the point of action of net force.

9. If any external force also is applied on the distributed loading then?

a) The net force will act at the centroid of the structure only

b) The net load will not be formed as all the forces will be cancelled

c) The net force will act on the base of the loading horizontally

d) The net force will not to be considered, there would be a net force of the distribution, rest will be the external forces

View Answer

Explanation: The external forces are treated differently. They are not added by the force of the distributed loading. That is the force not only acts at the centroid always. It can be shifted also. Depending on the external forces.

10. The resultant force acting, of the uniformly distributed loading, is dependent on:

a) Area

b) Vertical distance

c) Length of the supports

d) The distance of the supports between them

View Answer

Explanation: The resultant force acting, of the uniformly distributed loading, is dependent on the area that the distribution is covering. The more the area the more is the force. That is the more is the tension created over the structure on which loading is kept. Hence the answer.

11. The difference between the two types of loading namely uniformly distributed and the non-uniformly distributed loading is that:

a) The latter has the involvement of the integration for the calculation of the net force

b) The former has the involvement of the integration for the calculation of the net force

c) The latter has the involvement of the differentiation for the calculation of the net force

d) The former has the involvement of the differentiation for the calculation of the net force

View Answer

Explanation: The non-uniformly distributed loading is using the integration for getting the net force given by it. And the former only need the area or the linear distance of the loading. That is when the distance is multiplied by the uniformly distributed load the net force is obtained. But that is not so with the non-uniform one.

12. Determine the location of the resultant force acting on the shaft shown from left. The length is 2m.

a) 1.5m

b) 0.5m

c) 0.7m

d) 1.8m

View Answer

Explanation: The net force will act at the centroid of the parabola. Whether it be a parabola or the cubic curve the centroid is the only point at which the net force act. Force can’t be acted horizontally if the loading is vertical. Hence whatever be the shape of the loading, the centroid is the point of action of net force.

13. Determine the location of the resultant force acting on the shaft shown from left.

a) 4.5m

b) 4m

c) 3.5m

d) 2m

View Answer

Explanation: The net force will act at the centroid of the parabola. Whether it be a parabola or the cubic curve the centroid is the only point at which the net force act. Force can’t be acted horizontally if the loading is vertical. Hence whatever be the shape of the loading, the centroid is the point of action of net force.

15. Determine the magnitude of the resultant force acting on the shaft shown from left.

a) 1650N

b) 150N

c) 1250N

d) 1450N

View Answer

Explanation: The net force will act at the centroid of the parabola. Whether it be a parabola or the cubic curve the centroid is the only point at which the net force act. Force can’t be acted horizontally if the loading is vertical. Hence whatever be the shape of the loading, the centroid is the point of action of net force.

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