This set of Electric Drives Multiple Choice Questions & Answers (MCQs) focuses on “Dynamics – Steady State Stability of Electric Drive”.

1. A 4-pole lap wound generator with 720 armature conductors and a flux per pole of .003 Wb has an armature current of 50 A. The developed torque is _________

a) 17.25 N-m

b) 17.19 N-m

c) 16.54 N-m

d) 16.89 N-m

View Answer

Explanation: The developed torque in the motor is K

_{m}×I. The value of machine constant(K

_{m}) is E

_{b}÷ω

_{m}= Φ×Z×P÷2×3.14×A = .003×720×4÷2×3.14×4 = .3438 Vs/rad. The developed torque is .3438×50 = 17.19 N-m.

2. The generated e.m.f from 70-pole armature having 100 conductors driven at 10 rev/sec having flux per pole as 20 mWb, with wave winding is ___________

a) 730 V

b) 740 V

c) 700 V

d) 690 V

View Answer

Explanation: The generated e.m.f can be calculated using the formula E

_{b}= Φ×Z×N×P÷60×A, Φ represent flux per pole, Z represents the total number of conductors, P represents the number of poles, A represents the number of parallel paths, N represents speed in rpm. In wave winding number of parallel paths are 2. E

_{b}= .02×70×100×600÷60×2 = 700 V.

3. The unit of current is Tesla.

a) True

b) False

View Answer

Explanation: The current is the amount of charge that can flow through an area in a given amount of time. It is mathematically represented as d(q)/d(t). It is expressed in terms of Ampere.

4. Calculate the moment of inertia of the sphere having a mass of 12 kg and radius of 78 cm.

a) 7.888 kgm^{2}

b) 7.300 kgm^{2}

c) 7.545 kgm^{2}

d) 7.552 kgm^{2}

View Answer

Explanation: The moment of inertia of the egg can be calculated using the formula I=Σm

_{i}r

_{i}

^{2}. The mass of egg and radius is given. I=(12)×(.78)

^{2}=7.300 kgm

^{2}. It depends upon the orientation of the rotational axis.

5. The most suitable servo-motor application is __________

a) AC series motor

b) DC series motor

c) AC two-phase induction motor

d) DC shunt motor

View Answer

Explanation: DC shunt motor has definite no-load speed, so they don’t ‘run away’ when the load is suddenly thrown off provided the field circuit remains closed. The speed for any load within the operating range of the motor can be readily obtained.

6. In a DC series motor, the electromagnetic torque developed is proportional to ______

a) I_{a}

b) I_{a}^{2}

c) I_{a}^{3}

d) I_{a}^{.5}

View Answer

Explanation: In a DC series motor, the electromagnetic torque developed is equal to K

_{m}ΦI

_{a}. In a DC series, the motor field winding is connected in series with the armature so the flux in the field winding is proportional to current. T = K

_{m}ΦI

_{a}α I

_{a}

^{2}.

7. Calculate the value of the time period if the frequency of the signal is 70 sec.

a) 0.014 sec

b) 0.013 sec

c) 0.017 sec

d) 0.079 sec

View Answer

Explanation: The time period is defined as the time after the signal repeats itself. It is expressed in second. T = 1÷F=1÷70=.014 sec.

8. The slope of the V-I curve is 90°. Calculate the value of resistance.

a) 1.732 Ω

b) 1.608 Ω

c) 1.543 Ω

d) 1.648 Ω

View Answer

Explanation: The slope of the V-I curve is resistance. The slope given is 90° so R=tan(90°)=infinite Ω. It behaves as an open-circuit.

9. In a DC shunt motor, the electromagnetic torque developed is proportional to ______

a) I_{a}

b) I_{a}^{2}

c) I_{a}^{3}

d) I_{a}^{.5}

View Answer

Explanation: In a DC shunt motor, the electromagnetic torque developed is equal to K

_{m}ΦI

_{a}. In a DC shunt, the motor field windings are connected separately and excited by a constant DC voltage. T = K

_{m}ΦI

_{a}α I

_{a}.

**Sanfoundry Global Education & Learning Series – Electric Drives.**

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