This set of Electric Circuits Multiple Choice Questions & Answers (MCQs) focuses on “Kirchhoff’s Laws”.

1.KCL is based on the fact that

a) There is a possibility for a node to store energy.

b) There cannot be an accumulation of charge at a node.

c) Charge accumulation is possible at node

d) Charge accumulation may or may not be possible.

View Answer

Explanation: Since the node is not a circuit element, any charge which enters node must leave immediately.

2. Relation between currents according to KCL is

a) i_{1}=i_{2}=i_{3}=i_{4}=i_{5}

b) i_{1}+i_{4}+i_{3}=i_{5}+i_{2}

c) i_{1}-i_{5}=i_{2}-i_{3}-i_{4}

d) i_{1}+i_{5}=i_{2}+i_{3}+i_{4}

View Answer

Explanation: According to KCL, entering currents=leaving currents.

3. The algebraic sum of voltages around any closed path in a network is equal to ____________

a) Infinity

b) 1

c) 0

d) Negative polarity

View Answer

Explanation: According to KVL, the sum of voltages around the closed path in a network is zero.

4.

Calculate potential difference between x and y

a) 4.275v

b) -4.275v

c) 4.527v

d) -4.527v

View Answer

Explanation:

I

_{1}= 3/3+5 = 3/8 = 0.375Ω

I

_{2}= 4/5 = 0.8Ω

V

_{xy }= v

_{x}– v

_{y}

V

_{x}+ 5I

_{1}+ 4 – 2I

_{2}– v

_{y}= 0

V

_{x}– v

_{y}= 2I2 – 4 – 5I

_{1}= -4.275Ω

5.

Find R

a) 17.5 Ω

b) 17.2 Ω

c) 17.4 Ω

d) 17.8 Ω

View Answer

Explanation:

KVL: 70 – 5I – 7(I – 2) = 0

I = 7A

KVL to 2nd loop: 7(I – 2) – 2R = 0

R=17.5Ω

6. Determine currents I_{1} , I_{2} and I_{3}.

a) -3.3A, -8.5A, 2.4A

b) 3A, -8A, 2A

c) 3.3A, 8.5A, -2.4A

d) 3.2A, 8.6A, 2.3A

View Answer

Explanation:

I

_{1}= I

_{1}– I

_{2}+ 8 + I

_{3}+ 3

I

_{2}– I

_{3}= 11 -> 1

And -11 I1 – 7(I

_{1}– I

_{2}) = 0

-18 I

_{1}+ 7 I

_{2}= 0 -> 2

And -11 I

_{1}– 15 I

_{3}=0 -> 3

Solving I

_{1}= 3.32A I

_{2}= 8.5A I

_{3}= -2.4A.

7. All _____________ are loops but _______________ are not meshes

a) Loops, Meshes

b) Meshes, loops

c) Branches, loops

d) Nodes, Branches

View Answer

Explanation: A mesh cannot be divided further in loops.

8.

Solve for I.

a) -0.5A

b) 0.5A

c) -0.2A

d) 0.2A

View Answer

Explanation: V

_{eq}= 10 + 5 -20 = -5u

R

_{eq}= 5 + 2 + 3 = 10Ω

I = V/R = -5/10 = -0.5A.

9. The basic laws for analyzing an electric circuit are :-

a) Einstein’s theory

b) Newtons laws

c) Kirchhoff’s laws

d) Faradays laws

View Answer

Explanation: Kirchhoff’s laws are used for analyzing an electric circuit.

10. A junction whell two (or) more than two network elements meet is known as a ______________

a) Node

b) Branch

c) Loop

d) Mesh

View Answer

Explanation: Node is a junction where two or more than two network elements meet.

**Sanfoundry Global Education & Learning Series – Electric Circuits.**

To practice all areas of Electric Circuits, __here is complete set of 1000+ Multiple Choice Questions and Answers__.