Electric Circuits Questions and Answers – Kirchhoff’s Laws

This set of Electric Circuits Multiple Choice Questions & Answers (MCQs) focuses on “Kirchhoff’s Laws”.

1. KCL is based on the fact that
a) There is a possibility for a node to store energy.
b) There cannot be an accumulation of charge at a node.
c) Charge accumulation is possible at node
d) Charge accumulation may or may not be possible.
View Answer

Answer: b
Explanation: Since the node is not a circuit element, any charge which enters node must leave immediately.

2. Relation between currents according to KCL is
The symbol used for capacitance - option b
a) i1=i2=i3=i4=i5
b) i1+i4+i3=i5+i2
c) i1-i5=i2-i3-i4
d) i1+i5=i2+i3+i4
View Answer

Answer: d
Explanation: According to KCL, entering currents=leaving currents.

3. The algebraic sum of voltages around any closed path in a network is equal to ____________
a) Infinity
b) 1
c) 0
d) Negative polarity
View Answer

Answer: c
Explanation: According to KVL, the sum of voltages around the closed path in a network is zero.

4. Calculate potential difference between x and y
The potential difference between x & y is -4.275v
a) 4.275v
b) -4.275v
c) 4.527v
d) -4.527v
View Answer

Answer: b
Potential difference between x & y
I1 = 3/3+5 = 3/8 = 0.375Ω
I2 = 4/5 = 0.8Ω
Vxy = vx – vy
Vx + 5I1 + 4 – 2I2 – vy = 0
Vx – vy = 2I2 – 4 – 5I1 = -4.275Ω

5. Find R-value from the below circuit?
Find R-value from the circuit
a) 17.5 Ω
b) 17.2 Ω
c) 17.4 Ω
d) 17.8 Ω
View Answer

Answer: a
The R-value from the circuit is 17.5 appying KVL to 2nd loop
KVL: 70 – 5I – 7(I – 2) = 0
I = 7A
KVL to 2nd loop: 7(I – 2) – 2R = 0
Note: Join free Sanfoundry classes at Telegram or Youtube

6. Determine currents I1 , I2 and I3.
Find the currents I1 , I2 and I3 from the given diagram
a) -3.3A, -8.5A, 2.4A
b) 3A, -8A, 2A
c) 3.3A, 8.5A, -2.4A
d) 3.2A, 8.6A, 2.3A
View Answer

Answer: c
The currents I1, I2 & I3 is 3.3A, 8.5A & -2.4A
I1 = I1 – I2 + 8 + I3 + 3
I2 – I3 = 11 -> 1
And -11 I1 – 7(I1 – I2) = 0
-18 I1 + 7 I2 = 0 -> 2
And -11 I1 – 15 I3 =0 -> 3
Solving I1 = 3.32A I2 = 8.5A I3 = -2.4A.

7. All _____________ are loops but _______________ are not meshes
a) Loops, Meshes
b) Meshes, loops
c) Branches, loops
d) Nodes, Branches
View Answer

Answer: b
Explanation: A mesh cannot be divided further in loops.

8. Solve and find the value of I.
The value of I in given figure is -0.5A
a) -0.5A
b) 0.5A
c) -0.2A
d) 0.2A
View Answer

Answer: a
Explanation: Veq = 10 + 5 -20 = -5u
Req = 5 + 2 + 3 = 10Ω
I = V/R = -5/10 = -0.5A.

9. The basic laws for analyzing an electric circuit are :-
a) Einstein’s theory
b) Newtons laws
c) Kirchhoff’s laws
d) Faradays laws
View Answer

Answer: c
Explanation: Kirchhoff’s laws are used for analyzing an electric circuit.


10. A junction whell two (or) more than two network elements meet is known as a ______________
a) Node
b) Branch
c) Loop
d) Mesh
View Answer

Answer: a
Explanation: Node is a junction where two or more than two network elements meet.

Sanfoundry Global Education & Learning Series – Electric Circuits.

To practice all areas of Electric Circuits, here is complete set of 1000+ Multiple Choice Questions and Answers.

If you find a mistake in question / option / answer, kindly take a screenshot and email to [email protected]

Subscribe to our Newsletters (Subject-wise). Participate in the Sanfoundry Certification contest to get free Certificate of Merit. Join our social networks below and stay updated with latest contests, videos, internships and jobs!

Youtube | Telegram | LinkedIn | Instagram | Facebook | Twitter | Pinterest
Manish Bhojasia - Founder & CTO at Sanfoundry
Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He lives in Bangalore, and focuses on development of Linux Kernel, SAN Technologies, Advanced C, Data Structures & Alogrithms. Stay connected with him at LinkedIn.

Subscribe to his free Masterclasses at Youtube & discussions at Telegram SanfoundryClasses.