This set of Electric Circuits Questions and Answers for Experienced people focuses on “The Mesh-Current Method and Dependent Sources and Some Special Cases”.

1. The loop which does not contain any other inner loop is known as _____________

a) A node

b) A mesh

c) A branch

d) A super mesh

View Answer

Explanation: A mesh is defined as a loop which does not contain any other loop within it.

2. If there are 6 branches and 4 essential nodes, how many equations are required to describe a circuit in mesh-current method?

a) 3

b) 6

c) 4

d) 2

View Answer

Explanation: In Mesh-Current method, b-(n-1) equations are required to describe the circuit. b= the number of branches and n= the number of essential nodes.

3. Find the current flowing through 5Ω resistor in the given circuit.

a) 0.57A

b) 0.64A

c) 0.78A

d) 0.89A

View Answer

Explanation: There are 3 meshes in the given circuit. Assuming currents I

_{1}, I

_{2}, I

_{3}in the 3 meshes and by applying KVL, equations will be obtained which on solving gives the respective currents flowing in the circuits.

4. A Super Mesh analysis could be done when there is a common _____________ between any two loops.

a) Voltage source

b) Current source

c) Resistor

d) Both voltage and current source

View Answer

Explanation: A Super Mesh analysis could be done when there is a common current source between any two loops.

5. Calculate the current flowing through 10Ω resistor in the circuit shown below.

a) ±0.435A

b) ±0.985A

c) 1.217A

d) 2.782A

View Answer

Explanation: Loop2 and loop3 forms a supermesh.

Supermesh: I

_{3}-I

_{2}=4

Loop1: 11I

_{1}-10I

_{2}=2

KVL at Supermesh: -2I

_{1}+3I

_{2}+3I

_{3}=0

Solving these gives the currents flowing in the circuit and current through 10Ω resistor is either I

_{1}-I

_{2}or I

_{2}-I

_{1}.

6. Find the power delivered by the voltage source in the network given below.

a) 65Watts

b) 72Watts

c) 63Watts

d) 76Watts

View Answer

Explanation: 3 loops and a supermesh between loop1 and loop3. Using KVL currents are found out. I

_{1}=9A, I

_{2}=2.5A, I

_{3}=2A. As voltage source is in 1st loop, Power delivered by voltage source=V*I

_{1}.

7. The Mesh-Current method is applicable only for ___________

a) Non-linear networks

b) Equivalent networks

c) Non-planar networks

d) Planar networks

View Answer

Explanation: The Mesh-Current method is applicable only for Planar networks. A network is said to be planar if there are no crossovers in it and it can be drawn freely on a plane surface.

8. Find the value of V_{X} in the circuit given below.

a) –0.8A

b) +0.8A

c) -4.8A

d) +4.8A

View Answer

Explanation: Applying KVL, currents could be found out. I

_{1}=0.4A, I

_{2}=2.4A. V

_{X}=-I

_{1}R

_{1}.

9. A Supermesh is formed between two loops which share a common voltage source.

a) True

b) False

View Answer

Explanation: Meshes that share a current source with other meshes, none of which contains a current source in the outer loop, forms a supermesh.

10. If 4 equations are required to describe a circuit by Mesh-Current method and there are n nodes. How many branches are there in the network?

a) n+5

b) n+3

c) n

d) n-1

View Answer

Explanation: Standard formulae: b-(n-1)

Given b-(n-1) =4 -> b=4+ (n-1) =n+3.

11. If there are 16 branches and 5 essential nodes, how many equations are required to describe a circuit in mesh-current method?

a) 12

b) 16

c) 21

d) 9

View Answer

Explanation: In Mesh-Current method, b-(n-1) equations are required to describe the circuit. b=the number of branches and n= the number of essential nodes.

12. Determine the current through 3Ω resistor in the network given below.

a) 2A

b) 3A

c) 4A

d) -2A

View Answer

Explanation: Mesh1 and Mesh2 form a super mesh. Assuming currents I

_{1}and I

_{2}and applying KVL, the current through required resistor is found out.

13. Mesh analysis is best suitable for _____________

a) Current sources

b) Voltage sources

c) Complex elements

d) Unilateral elements

View Answer

Explanation: Mesh analysis is best suitable for Current sources.

**Sanfoundry Global Education & Learning Series – Electric Circuits.**

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