This is a C++ Program to implement interval tree. In computer science, an interval tree is an ordered tree data structure to hold intervals. Specifically, it allows one to efficiently find all intervals that overlap with any given interval or point. It is often used for windowing queries, for instance, to find all roads on a computerized map inside a rectangular viewport, or to find all visible elements inside a three-dimensional scene. A similar data structure is the segment tree.
Here is source code of the C++ Program to Implement Interval Tree. The C++ program is successfully compiled and run on a Linux system. The program output is also shown below.
#include <iostream>
using namespace std;
struct Interval
{
int low, high;
};
struct ITNode
{
Interval *i; // 'i' could also be a normal variable
int max;
ITNode *left, *right;
};
// A utility function to create a new Interval Search Tree Node
ITNode * newNode(Interval i)
{
ITNode *temp = new ITNode;
temp->i = new Interval(i);
temp->max = i.high;
temp->left = temp->right = NULL;
};
// A utility function to insert a new Interval Search Tree Node
// This is similar to BST Insert. Here the low value of interval
// is used tomaintain BST property
ITNode *insert(ITNode *root, Interval i)
{
// Base case: Tree is empty, new node becomes root
if (root == NULL)
return newNode(i);
// Get low value of interval at root
int l = root->i->low;
// If root's low value is smaller, then new interval goes to
// left subtree
if (i.low < l)
root->left = insert(root->left, i);
// Else, new node goes to right subtree.
else
root->right = insert(root->right, i);
// Update the max value of this ancestor if needed
if (root->max < i.high)
root->max = i.high;
return root;
}
// A utility function to check if given two intervals overlap
bool doOVerlap(Interval i1, Interval i2)
{
if (i1.low <= i2.high && i2.low <= i1.high)
return true;
return false;
}
// The main function that searches a given interval i in a given
// Interval Tree.
Interval *intervalSearch(ITNode *root, Interval i)
{
// Base Case, tree is empty
if (root == NULL)
return NULL;
// If given interval overlaps with root
if (doOVerlap(*(root->i), i))
return root->i;
// If left child of root is present and max of left child is
// greater than or equal to given interval, then i may
// overlap with an interval is left subtree
if (root->left != NULL && root->left->max >= i.low)
return intervalSearch(root->left, i);
// Else interval can only overlap with right subtree
return intervalSearch(root->right, i);
}
void inorder(ITNode *root)
{
if (root == NULL)
return;
inorder(root->left);
cout << "[" << root->i->low << ", " << root->i->high << "]" << " max = "
<< root->max << endl;
inorder(root->right);
}
int main(int argc, char **argv)
{
Interval ints[] = { { 15, 20 }, { 10, 30 }, { 17, 19 }, { 5, 20 },
{ 12, 15 }, { 30, 40 } };
int n = sizeof(ints) / sizeof(ints[0]);
ITNode *root = NULL;
for (int i = 0; i < n; i++)
root = insert(root, ints[i]);
cout << "In-order traversal of constructed Interval Tree is\n";
inorder(root);
Interval x = { 6, 7 };
cout << "\nSearching for interval [" << x.low << "," << x.high << "]";
Interval *res = intervalSearch(root, x);
if (res == NULL)
cout << "\nNo Overlapping Interval";
else
cout << "\nOverlaps with [" << res->low << ", " << res->high << "]";
}
Output:
$ g++ IntervalTree.cpp $ a.out In-order traversal of constructed Interval Tree is [5, 20] max = 20 [10, 30] max = 30 [12, 15] max = 15 [15, 20] max = 40 [17, 19] max = 40 [30, 40] max = 40 Searching for interval [6,7] Overlaps with [5, 20] ------------------ (program exited with code: 0) Press return to continue
Sanfoundry Global Education & Learning Series – 1000 C++ Programs.
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