This is a C++ to compute combinations using factorials.
Problem Description
1. This algorithm prints a total number of combination possible for given n and r value.
2. The time complexity of this algorithm is O(n).
Problem Solution
1. This algorithm takes the input of n and r value.
2. Print the result using ( n! / (r! * (n-r)!)).
3. Exit.
Program/Source Code
C++ Program to compute combinations using factorials.
This program is successfully run on Dev-C++ using TDM-GCC 4.9.2 MinGW compiler on a Windows system.
#include<iostream> using namespace std; // A function to find the factorial. int factorial(int n) { int i; for(i = n-1; i > 1; i--) n *= i; return n; } int main() { int n, r, result; cout<<"A program to find combination from nCr format using ( n! / (r! * (n-r)!))"; cout<<"\n\n\tEnter the value of n: "; cin>>n; cout<<"\tEnter the value of r: "; cin>>r; // Get result using formula to calculate combinations. result = factorial(n)/(factorial(r)*factorial(n-r)); cout<<"\nThe number of possible combinations is: "<<result; }
Program Explanation
1. Take the input of n and r.
2. Using factorial(), calculate values for n!, r! and (n-r)!.
3. Using ( n! / (r! * (n-r)!)), print the result.
4. Exit.
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Runtime Test Cases
Case 1: A program to find combination from nCr format using ( n! / (r! * (n-r)!)) Enter the value of n: 5 Enter the value of r: 3 The number of possible combinations is: 10 Case 2: A program to find combination from nCr format using ( n! / (r! * (n-r)!)) Enter the value of n: 13 Enter the value of r: 4 The number of possible combinations is: 221
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