This C++ Program Checks if a Binary Tree is a Binary Search Tree.
Here is source code of the C++ Program to check if a Binary Tree is a BST. The C++ program is successfully compiled and run on a Linux system. The program output is also shown below.
/*
* C++ Program to Check if a Binary Tree is a BST
*/
#include <iostream>
#include <cstdlib>
#include <climits>
using namespace std;
/*
* Node Declaration
*/
struct node
{
int data;
node* left;
node* right;
};
int isBSTUtil(node* node, int min, int max);
/*
* Returns true if the given tree is a binary search tree
*/
int isBST(node* node)
{
return(isBSTUtil(node, INT_MIN, INT_MAX));
}
/*
* Returns true if the given tree is a BST and its
* values are >= min and <= max.
*/
int isBSTUtil(struct node* node, int min, int max)
{
if (node==NULL)
return 1;
if (node->data < min || node->data > max)
return 0;
return isBSTUtil(node->left, min, node->data - 1) &&
isBSTUtil(node->right, node->data + 1, max);
}
/*
* allocates a new node with the data and NULL left and right pointers.
*/
node* newNode(int data)
{
node* nod = new node;
nod->data = data;
nod->left = NULL;
nod->right = NULL;
return nod;
}
/*
* Main
*/
int main()
{
node *root = newNode(4);
root->left = newNode(2);
root->right = newNode(5);
root->left->left = newNode(1);
root->left->right = newNode(3);
if (isBST(root))
cout<<"The Given Binary Tree is a BST"<<endl;
else
cout<<"The Given Binary Tree is not a BST"<<endl;
return 0;
}
$ g++ binary_bst.cpp $ a.out The Given Binary Tree is a BST ------------------ (program exited with code: 1) Press return to continue
Sanfoundry Global Education & Learning Series – 1000 C++ Programs.
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