This set of Chemical Process Calculation Multiple Choice Questions & Answers (MCQs) focuses on “Mole and Molecular Weight – VI”.
1. A cylinder contains 56 g of N2. What is the number of moles of N2 present in the cylinder?
a) 1
b) 2
c) 4
d) 6
View Answer
Explanation: Number of moles = mass / molecular weight = 56 / 28 = 2.
2. A cylinder contains 128 g of O2. What is the number of moles of O2 present in the cylinder?
a) 1
b) 2
c) 4
d) 6
View Answer
Explanation: Number of moles = mass / molecular weight = 128 / 64 = 2.
3. A cylinder contains 64 g of SO2. What is the number of moles of SO2 present in the cylinder?
a) 1
b) 2
c) 4
d) 6
View Answer
Explanation: Number of moles = mass / molecular weight = 64 / 64 = 1.
4. If a cylinder contains 2 moles of O2 and 1 mole of SO2, what is the total number of moles of oxygen atoms present in the cylinder?
a) 1
b) 2
c) 3
d) 4
View Answer
Explanation: Each molecule of O2 and SO2 contributes 2 and 1 mole of oxygen atoms, respectively. Total moles of oxygen atoms = 2 + 1 = 3.
5. A cylinder contains 1 mole of SO2. What is the number of moles of sulfur atoms in the cylinder?
a) 1
b) 2
c) 4
d) 6
View Answer
Explanation: Each molecule of SO2 has one sulfur atom, so the number of moles of sulfur is the same as the number of moles of SO2.
6. In a mixture with 2 moles of N2, 2 moles of O2, and 1 mole of SO2, what is the mole fraction of N2?
a) 0.2
b) 0.4
c) 0.6
d) 0.8
View Answer
Explanation: Mole fraction = moles of N2 / total moles = 2 / (2 + 2 + 1) = 2 / 5 = 0.4.
7. In a mixture with 2 moles of N2, 2 moles of O2, and 1 mole of SO2, what is the mole fraction of O2?
a) 0.2
b) 0.4
c) 0.6
d) 0.8
View Answer
Explanation: Mole fraction = moles of O2 / total moles = 2 / (2 + 2 + 1) = 2 / 5 = 0.4.
8. In a mixture with 2 moles of N2, 2 moles of O2, and 1 mole of SO2, what is the mole fraction of SO2?
a) 0.2
b) 0.4
c) 0.6
d) 0.8
View Answer
Explanation: Mole fraction = moles of SO2 / total moles = 1 / (2 + 2 + 1) = 1 / 5 = 0.2.
9. A cylinder contains 56 g of N2, with a total mass of all components equal to 248 g. What is the weight percentage of N2 in the cylinder?
a) 22.58
b) 25.86
c) 42.56
d) 54.87
View Answer
Explanation: Weight percentage = (mass of N2 / total mass) × 100 = (56 / 248) × 100 ≈ 22.58.
10. A cylinder contains 128 g of O2, with a total mass of all components equal to 248 g. What is the weight percentage of O2 in the cylinder?
a) 51.61
b) 61.71
c) 71.81
d) 81.91
View Answer
Explanation: Weight percentage = (mass of O2 / total mass) × 100 = (128 / 248) × 100 ≈ 51.61.
Sanfoundry Global Education & Learning Series – Chemical Process Calculation.
To practice all areas of Chemical Process Calculation, here is complete set of 1000+ Multiple Choice Questions and Answers.
