This set of Chemical Process Calculation Multiple Choice Questions & Answers (MCQs) focuses on “Material Balance without Reaction-II”.
1. In a reactor, the feed consists of NaOH, H2O, and HCl, with a total mass of 800 kg. The mass fractions of NaOH, H2O, and HCl in the feed are 0.3, 0.5, and 0.2, respectively. What is the amount of NaOH in the feed?
a) 240 Kg
b) 480 Kg
c) 560 Kg
d) 800 Kg
View Answer
Explanation: Mass of NaOH = Total feed mass × Mass fraction of NaOH = 800 kg × 0.3 = 240 kg.
2. In a reactor, the feed consists of NaOH, H2O, and HCl, with a total mass of 800 kg. The mass fractions of NaOH, H2O, and HCl in the feed are 0.3, 0.5, and 0.2, respectively. What is the amount of HCl in the feed?
a) 80 Kg
b) 160 Kg
c) 240 Kg
d) 320 Kg
View Answer
Explanation: Mass of HCl = Total feed mass × Mass fraction of HCl = 800 kg × 0.2 = 160 kg.
3. In a reactor, the feed consists of NaOH, H2O, and HCl, with a total mass of 800 kg. The mass fractions of NaOH, H2O, and HCl in the feed are 0.3, 0.5, and 0.2, respectively. What is the amount of H2O in the feed?
a) 100 Kg
b) 200 Kg
c) 400 Kg
d) 800 Kg
View Answer
Explanation: Mass of H2O = Total feed mass × Mass fraction of H2O = 800 kg × 0.5 = 400 kg.
4. In a reaction system, the total product mass is 400 kg, with 300 kg of H2O recovered. If the mass ratio of NaOH to HCl in the product is 0.6, what is the amount of NaOH in the product?
a) 21.5 Kg
b) 31.5 Kg
c) 37.5 Kg
d) 40.5 Kg
View Answer
Explanation: Let the masses of NaOH and HCl in the product be x and y respectively. Given x/y=0.6 and x+y=100 kg (400 kg total – 300 kg of H2O), solve for x=37.5 kg.
5. In a reaction system, the total product mass is 400 kg, with 300 kg of H2O recovered. If the mass ratio of NaOH to HCl in the product is 0.6, what is the amount of HCl in the product?
a) 62.5 Kg
b) 56.5 Kg
c) 40.5 Kg
d) 32.5 Kg
View Answer
Explanation: From the equation x+y=100 kg and x/y=0.6, solve for y=62.5 kg of HCl.
6. A reactor feed of 800 kg contains NaOH, H2O, and HCl, and produces 400 kg of product, with 300 kg of H2O in the product. If the amount of NaOH in the product is 37.5 kg, how many kg of NaOH remain in the reactor?
a) 101.5 Kg
b) 202.5 Kg
c) 303.5 Kg
d) 404.5 Kg
View Answer
Explanation: Initial NaOH = 240 kg. NaOH in product = 37.5 kg, so NaOH remaining = 240 kg – 37.5 kg = 202.5 kg.
7. A reactor feed of 800 kg contains NaOH, H22O, and HCl, and produces 400 kg of product, with 300 kg of H2O in the product. If the amount of HCl in the product is 62.5 kg, how many kg of HCl remain in the reactor?
a) 111.5 Kg
b) 122.5 Kg
c) 133.5 Kg
d) 144.5 Kg
View Answer
Explanation: Initial HCl = 160 kg. HCl in product = 62.5 kg, so HCl remaining = 160 kg – 62.5 kg = 122.5 kg.
8. A reactor feed of 800 kg contains NaOH, H2O, and HCl, and produces 400 kg of product, with 300 kg of H2O in the product. How many kg of H2O remain in the reactor?
a) 100 Kg
b) 200 Kg
c) 300 Kg
d) 400 Kg
View Answer
Explanation: Initial H2O = 400 kg. H2O in product = 300 kg, so H2O remaining = 400 kg – 300 kg = 100 kg.
Sanfoundry Global Education & Learning Series – Chemical Process Calculation.
To practice all areas of Chemical Process Calculation, here is complete set of 1000+ Multiple Choice Questions and Answers.
