Chemical Engineering Questions and Answers – Ideal Gas Law

This set of Basic Chemical Engineering Multiple Choice Questions & Answers (MCQs) focuses on “Ideal Gas Law”.

1. Which of the following term does not involve in ideal gas law?
a) Pressure
b) Volume
c) Temperature
d) Time
View answer

Answer: d
Explanation: Ideal gas law is PV = nRT, which does not involve time.

2. What is the shape of a P-T curve for ideal gas?
a) Straight line
b) Parabolic
c) Hyperbolic
d) Ellipse
View answer

Answer: a
Explanation: P-T curve is a straight line for ideal gas.

3. What is the shape of a V-T curve for ideal gas?
a) Straight line
b) Parabolic
c) Hyperbolic
d) Ellipse
View answer

Answer: a
Explanation: V-T curve is straight line for ideal gas.
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4. What is the shape of a P-V curve for an ideal gas?
a) Straight line
b) Parabolic
c) Hyperbolic
d) Ellipse
View answer

Answer: c
Explanation: P-V curve is hyperbolic for an ideal gas.

5. Which of the following is not true about ideal gas molecules?
a) They have negligible size
b) They do not have attractive forces
c) They do not apply pressure
d) They move in random motion
View answer

Answer: c
Explanation: Ideal gas molecules apply pressure to the walls of a container.
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6. What is the pressure of a 5 liter/mole ideal gas at temperature 27oC?
a) 2.5 atm
b) 3.8 atm
c) 4.4 atm
d) 5.3 atm
View answer

Answer: d
Explanation: PV = nRT, => P*5 = 0.0821*300, => P = 5.3 atm.

7. What is the Temperature of a 2 liter/mole ideal gas with pressure 10 atm?
a) 243.6 K
b) 268.4 K
c) 289.1 K
d) 313.5 K
View answer

Answer: a
Explanation: PV = nRT, => 10*2 = 0.0821*T, => T = 243.6 K.
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8. First of the two ideal gases has twice molar volume as much as the second at same temperature, what is the ratio of their pressures?
a) 4:1
b) 1:4
c) 2:1
d) 1:2
View answer

Answer: d
Explanation: P1V1 = n1RT1, P2V2 = n2RT2 dividing both the equations, => P1:P2 = 1:2.

9. 88 grams of CO2 at 27oC is applying 5 atm pressure, what is the volume occupied by it?
a) 5.6 liter
b) 7.9 liter
c) 9.8 liter
d) 12.2 liter
View answer

Answer: c
Explanation: n = 88/44 = 2, PV = nRT, => 5*V = 2*0.0821*300, => V = 9.8 liter.
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10. What is the density of O2 at 27oC with pressure 1 atm?
a) 1.1 g/L
b) 1.3 g/L
c) 1.5 g/L
d) 1.7 g/L
View answer

Answer: b
Explanation: Molecular wt. of O2= 44 g, PV = nRT, => PV = (m/M)RT, => d = PM/RT = (1*32)/(0.0821*300) = 1.3 g/L.

11. What is the molecular mass of an ideal gas with pressure 1 atm, and density 10 g/L at temperature 27oC?
a) 84.5 g
b) 135.1 g
c) 186.8 g
d) 246.3 g
View answer

Answer: d
Explanation: M = dRT/P = 10*0.0821*300/1 = 246.3 g.

12. What is the specific gravity of CO2 at 27oC and pressure 1 atm with respect to air of with density 1 g/L?
a) 1.23
b) 1.55
c) 1.78
d) 1.96
View answer

Answer: c
Explanation: Density of CO2 = PM/RT = 1*44/(0.0821*300) = 1.78 g/L, => Specific gravity = 1.78/1 = 1.78.

13. What is the specific gravity of CO at 27oC and pressure 5 atm with respect to air (molecular wt. = 29 g) at 27oC and pressure 10 atm?
a) 0.48
b) 0.56
c) 0.64
d) 0.72
View answer

Answer: a
Explanation: Density of CO = 5*28/(0.0821*300) = 5.68 g/L, density of air = 10*29/(0.0821*300) = 11.77 g/L, => specific gravity = 5.68/11.77 = 0.48.

14. What is the compressibility factor for an ideal gas?
a) 1
b) 2
c) 3
d) Depends on the gas
View answer

Answer: a
Explanation: Compressibility of an ideal gas is always 1.

15. Which of the following is not the unit of R?
a) Atm.liter/K.mole
b) Pa.m3/K
c) N.Kg.m3/K.mole
d) None of the mentioned
View answer

Answer: c
Explanation: N.Kg.m/K.mole is the unit of R.

Sanfoundry Global Education & Learning Series – Basic Chemical Engineering.

To practice all areas of Basic Chemical Engineering, here is complete set of 1000+ Multiple Choice Questions and Answers.

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Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He lives in Bangalore, and focuses on development of Linux Kernel, SAN Technologies, Advanced C, Data Structures & Alogrithms. Stay connected with him at LinkedIn.

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