Pointer Arrays Initialization - C Programming Questions and Answers

This set of C Multiple Choice Questions & Answers (MCQs) focuses on “Initialization of Pointer Arrays – 1”.

Pre-requisite for C Pointer Arrays Initialization MCQ set: Video Tutorial on C Pointers.

1. Which of the following is the correct syntax to declare a 3 dimensional array using pointers?
a) char *a[][];
b) char **a[];
c) char ***a;
d) all of the mentioned
View Answer

Answer: a
Explanation: None.

2. What will be the output of the following C code?

```
    #include <stdio.h>
```
```
    int main()
```
```
    {
```

        char *a = {"p", "r", "o", "g", "r", "a", "m"};

```
        printf("%s", a);
```
```
    }
```

a) Output will be program
b) Output will be p
c) No output
d) Compile-time error
View Answer

Answer: b
Explanation: None.

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3. An array of strings can be initialized by _________
a) char *a[] = {“Hello”, “World”};
b) char *a[] = {“Hello”, “Worlds”};
c)

char *b = "Hello";
char *c = "World";
char *a[] = {b, c};

d) all of the mentioned
View Answer

Answer: d
Explanation: None.

4. What will be the output of the following C code?

```
    #include <stdio.h>
```
```
    void main()
```
```
    {
```

        char *a[10] = {"hi", "hello", "how"};

```
        int i = 0;
```
```
        for (i = 0;i < 10; i++)
```
```
        printf("%s", *(a[i]));
```
```
    }
```

a) segmentation fault
b) hi hello how followed by 7 null values
c) 10 null values
d) depends on compiler
View Answer

Answer: a
Explanation: None.

5. What will be the output of the following C code?

```
    #include <stdio.h>
```
```
    void main()
```
```
    {
```

        char *a[10] = {"hi", "hello", "how"};

```
        int i = 0, j = 0;
```
```
        a[0] = "hey";
```
```
        for (i = 0;i < 10; i++)
```
```
        printf("%s\n", a[i]);
```
```
    }
```

a) hi hello how Segmentation fault
b) hi hello how followed by 7 null values
c) hey hello how followed by 7 null values
d) hey hello how Segmentation fault
View Answer

Answer: c
Explanation: None.

6. What will be the output of the following C code on a 32-bit system?

```
    #include <stdio.h>
```
```
    void main()
```
```
    {
```

        char *a[10] = {"hi", "hello", "how"};

```
        printf("%d\n", sizeof(a));
```
```
    }
```

a) 10
b) 13
c) Run time error
d) 40
View Answer

Answer: d
Explanation: If the system is 32-bit system, then the size of pointer will be 4 bytes. For such a system, the size of array a will be 4×10 = 40 bytes. The size of pointer is 8 bytes on a 64 bit system. For the given array a of 10 elements, it will be 8×10 = 80 bytes.

7. What will be the output of the following C code on a 32-bit system?

```
    #include <stdio.h>
```
```
    void main()
```
```
    {
```

        char *a[10] = {"hi", "hello", "how"};

```
        printf("%d\n", sizeof(a[1]));
```
```
    }
```

a) 6
b) 4
c) 5
d) 3
View Answer

Answer: b
Explanation: Array element a[1] is storing an address of character pointer. For a 32-bit systems its 4 bytes and for a 64-bit system, its 8 bytes.

8. What will be the output of the following C code?

```
    #include <stdio.h>
```
```
    void main()
```
```
    {
```

        char *a[10] = {"hi", "hello", "how"};

```
        int i = 0;
```
```
        for (i = 0;i < 10; i++)
```
```
        printf("%s", a[i]);
```
```
    }
```

a) hi hello how Segmentation fault
b) hi hello how null
c) hey hello how Segmentation fault
d) hi hello how followed by 7 nulls
View Answer

Answer: d
Explanation: None.

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