This is a C program to find sum of digits of a number using recursion.

This C program finds the sum of digits of a number using recursion.

The following C program, using recursion, finds the sum of its digits.

Here is the source code of the C program to find an element in a linked list. The C Program is successfully compiled and run on a Linux system. The program output is also shown below.

/* * C Program to find Sum of Digits of a Number using Recursion */ #include <stdio.h> int sum (int a); int main() { int num, result; printf("Enter the number: "); scanf("%d", &num); result = sum(num); printf("Sum of digits in %d is %d\n", num, result); return 0; } int sum (int num) { if (num != 0) { return (num % 10 + sum (num / 10)); } else { return 0; } }

In this C program, we are reading the integer number using the ‘num’ variable. The function sum() is used to find sum of digits of a number using recursion.

In function sum() check the value of ‘num’ variable is not equal to 0. If the condition is true execute the statement. Divide the value of ‘num’ variable by 10 integer value. Add the resulted value along with the modulus of the value of ‘num’ variable. Print the sum of digits of a number using recursion.

$ cc pgm25.c $ a.out Enter the number: 2345 Sum of digits in 2345 is 14

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