Gauss Jordan Elimination in C

This C program implements Gauss Jordan Elimination method. In linear algebra, Gaussian elimination is an algorithm for solving systems of linear equations.

Here is the source code of the C program to find solution of a system of linear equations. The C program is successfully compiled and run on a Linux system. The program output is also shown below.

```
#include<stdio.h>
```
```
 
```
```
void solution( int a[][20], int var );
```
```
int main()
```
```
{
```
```
 
```

    int a[ 20 ][ 20 ], var, i, j, k, l, n;

    printf( "\nEnter the number of variables:\n" );

```
    scanf( "%d", &var );
```
```
 
```
```
    for ( i = 0;i < var;i++ )
```
```
    {
```

        printf( "\nEnter the equation%d:\n", i + 1 );

```
 
```
```
        for ( j = 0;j < var;j++ )
```
```
        {
```

            printf( "Enter the coefficient of  x%d:\n", j + 1 );

            scanf( "%d", &a[ i ][ j ] );

```
        }
```
```
 
```

        printf( "\nEnter the constant:\n" );

```
        scanf( "%d", &a[ i ][ var] );
```
```
    }
```
```
 
```
```
    solution( a, var );
```
```
    return 0;
```
```
}
```
```
 
```
```
 
```
```
 
```

void solution( int a[ 20 ][ 20 ], int var )

```
{
```
```
    int k, i, l, j;
```
```
 
```
```
    for ( k = 0;k < var;k++ )
```
```
    {
```
```
        for ( i = 0;i <= var;i++ )
```
```
        {
```
```
            l = a[ i ][ k ];
```
```
 
```
```
            for ( j = 0;j <= var;j++ )
```
```
            {
```
```
                if ( i != k )
```

                a[i][j] = (a[k][k]*a[i][j])-(l*a[k][j]);

```
            }
```
```
        }
```
```
    }
```
```
 
```
```
    printf( "\nSolutions:" );
```
```
 
```
```
    for ( i = 0;i < var;i++ )
```
```
    {
```

        printf( "\nTHE VALUE OF x%d IS %f\n", i + 1, ( float ) a[ i ][ var ] / ( float ) a[ i ][ i ] );

```
    }
```
```
 
```
```
}
```

$ gcc bubblesort.c -o bubblesort
$ ./bubblesort
 
Enter the number of variables: 3
 
Enter the equation 1:
Enter the coefficient of  x1: 1 
Enter the coefficient of  x2: 0
Enter the coefficient of  x3: 0
 
Enter the constant: 2
 
Enter the equation 2:
Enter the coefficient of  x1: 0
Enter the coefficient of  x2: 1 
Enter the coefficient of  x3: 0
 
Enter the constant: 0
 
Enter the equation 3:
Enter the coefficient of  x1: 0
Enter the coefficient of  x2: 0
Enter the coefficient of  x3: 1
 
Enter the constant: -1
 
Solutions:
THE VALUE OF x1 IS 2.000000
 
THE VALUE OF x2 IS 0.000000
 
THE VALUE OF x3 IS -1.000000

Sanfoundry Global Education & Learning Series – 1000 C Programs.

Here’s the list of Best Books in C Programming, Data Structures and Algorithms.

If you find any mistake above, kindly email to [email protected]

« Prev - Solving Linear Equations in One Variable Using C

» Next - C Program to Implement Gauss Seidel Method

Related Posts:

Recommended Articles: