This is a C Program to multiply two signed numbers using booth’s algorithm. Booth’s multiplication algorithm is a multiplication algorithm that multiplies two signed binary numbers in two’s complement notation. Booth used desk calculators that were faster at shifting than adding and created the algorithm to increase their speed. Booth’s algorithm is of interest in the study of computer architecture.
Here is the source code of the C program to multiply two signed numbers using booth’s algorithm. The C program is successfully compiled and run on a Linux system. The program output is also shown below.
#include <stdio.h>
#include <math.h>
int a = 0,b = 0, c = 0, a1 = 0, b1 = 0, com[5] = { 1, 0, 0, 0, 0};
int anum[5] = {0}, anumcp[5] = {0}, bnum[5] = {0};
int acomp[5] = {0}, bcomp[5] = {0}, pro[5] = {0}, res[5] = {0};
void binary(){
a1 = fabs(a);
b1 = fabs(b);
int r, r2, i, temp;
for (i = 0; i < 5; i++){
r = a1 % 2;
a1 = a1 / 2;
r2 = b1 % 2;
b1 = b1 / 2;
anum[i] = r;
anumcp[i] = r;
bnum[i] = r2;
if(r2 == 0){
bcomp[i] = 1;
}
if(r == 0){
acomp[i] =1;
}
}
//part for two's complementing
c = 0;
for ( i = 0; i < 5; i++){
res[i] = com[i]+ bcomp[i] + c;
if(res[i] >= 2){
c = 1;
}
else
c = 0;
res[i] = res[i] % 2;
}
for (i = 4; i >= 0; i--){
bcomp[i] = res[i];
}
//in case of negative inputs
if (a < 0){
c = 0;
for (i = 4; i >= 0; i--){
res[i] = 0;
}
for ( i = 0; i < 5; i++){
res[i] = com[i] + acomp[i] + c;
if (res[i] >= 2){
c = 1;
}
else
c = 0;
res[i] = res[i]%2;
}
for (i = 4; i >= 0; i--){
anum[i] = res[i];
anumcp[i] = res[i];
}
}
if(b < 0){
for (i = 0; i < 5; i++){
temp = bnum[i];
bnum[i] = bcomp[i];
bcomp[i] = temp;
}
}
}
void add(int num[]){
int i;
c = 0;
for ( i = 0; i < 5; i++){
res[i] = pro[i] + num[i] + c;
if (res[i] >= 2){
c = 1;
}
else{
c = 0;
}
res[i] = res[i]%2;
}
for (i = 4; i >= 0; i--){
pro[i] = res[i];
printf("%d",pro[i]);
}
printf(":");
for (i = 4; i >= 0; i--){
printf("%d", anumcp[i]);
}
}
void arshift(){//for arithmetic shift right
int temp = pro[4], temp2 = pro[0], i;
for (i = 1; i < 5 ; i++){//shift the MSB of product
pro[i-1] = pro[i];
}
pro[4] = temp;
for (i = 1; i < 5 ; i++){//shift the LSB of product
anumcp[i-1] = anumcp[i];
}
anumcp[4] = temp2;
printf("\nAR-SHIFT: ");//display together
for (i = 4; i >= 0; i--){
printf("%d",pro[i]);
}
printf(":");
for(i = 4; i >= 0; i--){
printf("%d", anumcp[i]);
}
}
void main(){
int i, q = 0;
printf("\t\tBOOTH'S MULTIPLICATION ALGORITHM");
printf("\nEnter two numbers to multiply: ");
printf("\nBoth must be less than 16");
//simulating for two numbers each below 16
do{
printf("\nEnter A: ");
scanf("%d",&a);
printf("Enter B: ");
scanf("%d", &b);
}while(a >=16 || b >=16);
printf("\nExpected product = %d", a * b);
binary();
printf("\n\nBinary Equivalents are: ");
printf("\nA = ");
for (i = 4; i >= 0; i--){
printf("%d", anum[i]);
}
printf("\nB = ");
for (i = 4; i >= 0; i--){
printf("%d", bnum[i]);
}
printf("\nB'+ 1 = ");
for (i = 4; i >= 0; i--){
printf("%d", bcomp[i]);
}
printf("\n\n");
for (i = 0;i < 5; i++){
if (anum[i] == q){//just shift for 00 or 11
printf("\n-->");
arshift();
q = anum[i];
}
else if(anum[i] == 1 && q == 0){//subtract and shift for 10
printf("\n-->");
printf("\nSUB B: ");
add(bcomp);//add two's complement to implement subtraction
arshift();
q = anum[i];
}
else{//add ans shift for 01
printf("\n-->");
printf("\nADD B: ");
add(bnum);
arshift();
q = anum[i];
}
}
printf("\nProduct is = ");
for (i = 4; i >= 0; i--){
printf("%d", pro[i]);
}
for (i = 4; i >= 0; i--){
printf("%d", anumcp[i]);
}
}
$ gcc booth.c -o booth $ ./booth BOOTHS MULTIPLICATION ALGORITHM Enter two numbers to multiply: 12 12 Both must be less than 16 Enter A: Enter B: Expected product = 144 Binary Equivalents are: A = 01100 B = 01100 B'' + 1 = 10100 --> AR-SHIFT: 00000:00110 --> AR-SHIFT: 00000:00011 --> SUB B: 10100:00011 AR-SHIFT: 11010:00001 --> AR-SHIFT: 11101:00000 --> ADD B: 01001:00000 AR-SHIFT: 00100:10000 Product is = 0010010000
Sanfoundry Global Education & Learning Series – 1000 C Programs.
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