C Program to Find the Frequency of Every Word in a given String

This C Program finds frequency of every word in a given string.

Here is source code of the C Program to find the frequency of every word in a given string. The C program is successfully compiled and run on a Linux system. The program output is also shown below.

```
/* 
```

 * C Program to Find the Frequency of  Every Word in a

```
 * given String
```
```
 */
```
```
#include <stdio.h>
```
```
#include <string.h>
```
```
 
```
```
void main()
```
```
{
```

    int count = 0, c = 0, i, j = 0, k, space = 0;

```
 
```

    char str[100], p[50][100], str1[20], ptr1[50][100];

```
 
```
```
    char *ptr;
```
```
 
```
```
    printf("Enter the string\n");
```
```
    scanf(" %[^\n]s", str);
```
```
 
```

    printf("string length is %d\n", strlen(str));

```
 
```
```
    for (i = 0;i<strlen(str);i++)
```
```
    {
```

        if ((str[i] == ' ')||(str[i] == ',' && str[i+1] == ' ')||(str[i] == '.'))

```
        {
```
```
            space++;
```
```
        }
```
```
    }
```
```
 
```

    for (i = 0, j = 0, k = 0;j < strlen(str);j++)

```
    {
```

        if ((str[j] == ' ')||(str[j] == 44)||(str[j] == 46))

```
        {    
```
```
            p[i][k] = '\0';
```
```
            i++;
```
```
            k = 0;
```
```
        }        
```
```
        else
```
```
             p[i][k++] = str[j];
```
```
    }
```
```
 
```
```
    k = 0;
```
```
 
```
```
    for (i = 0;i <= space;i++)
```
```
    {
```
```
        for (j = 0;j <= space;j++)
```
```
        {
```
```
            if (i == j)
```
```
            {
```
```
                strcpy(ptr1[k], p[i]);
```
```
                k++;
```
```
                count++;
```
```
 
```
```
                break;
```
```
            }
```
```
            else
```
```
            {
```

                if (strcmp(ptr1[j], p[i]) != 0)

```
                    continue;
```
```
                else
```
```
                    break;
```
```
            }
```
```
        }
```
```
    }
```
```
 
```
```
    for (i = 0;i < count;i++) 
```
```
    {
```
```
        for (j = 0;j <= space;j++)
```
```
        {
```

            if (strcmp(ptr1[i], p[j]) == 0)

```
                c++;
```
```
        }
```

        printf("%s -> %d times\n", ptr1[i], c);

```
        c = 0;
```
```
    }
```
```
}
```

Enter the string:
Welcome to Sanfoundry Welcome to C Class
string length is 40
Welcome -> 2 times
to -> 2 times
Sanfoundry -> 1 times
C -> 1 times
Class -> 1 times
 
Enter the string:
Welcome to C Class, Java Class
string length is 30
Welcome -> 1 times
to -> 1 times
C -> 1 times
Class -> 2 times
 -> 1 times
Java -> 1 times

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