This C program, using iteration, displays a linked list. A linked list is an ordered set of data elements, each containing a link to its successor.
Here is the source code of the C program to display a linked list. The C program is successfully compiled and run on a Linux system. The program output is also shown below.
/*
* C Program to Display all the Nodes in a Linked List without using
* Recursion
*/
#include <stdio.h>
#include <stdlib.h>
struct node
{
int a;
struct node *next;
};
void generate(struct node **);
void display(struct node*);
void delete(struct node **);
int main()
{
struct node *head = NULL;
generate(&head);
display(head);
delete(&head);
return 0;
}
void generate(struct node **head)
{
int num = 10, i;
struct node *temp;
for (i = 0; i < num; i++)
{
temp = (struct node *)malloc(sizeof(struct node));
temp->a = i;
if (*head == NULL)
{
*head = temp;
(*head)->next = NULL;
}
else
{
temp->next = *head;
*head = temp;
}
}
}
void display(struct node *head)
{
while (head != NULL)
{
printf("%d ", head->a);
head = head->next;
}
printf("\n");
}
void delete(struct node **head)
{
struct node *temp;
while (*head != NULL)
{
temp = *head;
*head = (*head)->next;
free(temp);
}
}
$ gcc linkdisplay.c -o linkdisplay $ a.out 9 8 7 6 5 4 3 2 1 0
Sanfoundry Global Education & Learning Series – 1000 C Programs.
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If you wish to look at other example programs on Linked List, go to Linked List. If you wish to look at programming examples on all topics, go to C Programming Examples.
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